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Anna [14]
3 years ago
10

30 people go for dinner it costs £240.93 how much should each person pay

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0
The answer is 8.031 per person 
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An elliptically shaped garden is surrounded by a wood walkway. The garden is 15 meters long and 8 meters wide. The walkway is 2.
fiasKO [112]

Answer:

x^2/b^2 + y^2/a^a = 1

Step-by-step explanation:

I believe that is the answer, also theanswerme answered this question. :)

7 0
2 years ago
Lisa purchased a hat for $10, a purse for $20, and a book for $23.The sales-tax rate was 7.2 percent. What was the total amount
Vlad [161]

From information given Lisa bought three items.

10 + 20 + 23 = 53 dollars ( which is total pre- tax cost)

The sales tax rate is at 7.2% . Value of this tax in dollars will be:

7.2 % of 53 →  (7.2 / 100) × 53  →  0.072 × 53 =  3.816

So the tax rate value is 3.816

Total cost of items will be 53 + 3.816 =  56. 816

Rounded off  to the nearest cent 56.816   =  56.80

Therefore Lisa paid a total of $ 56.80


 

8 0
3 years ago
Find the locus of a point such that the sum of its distance from the point ( 0 , 2 ) and ( 0 , -2 ) is 6.
jok3333 [9.3K]

Answer:

\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1

Step-by-step explanation:

We want to find the locus of a point such that the sum of the distance from any point P on the locus to (0, 2) and (0, -2) is 6.

First, we will need the distance formula, given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let the point on the locus be P(x, y).

So, the distance from P to (0, 2) will be:

\begin{aligned} d_1&=\sqrt{(x-0)^2+(y-2)^2}\\\\ &=\sqrt{x^2+(y-2)^2}\end{aligned}

And, the distance from P to (0, -2) will be:

\displaystyle \begin{aligned} d_2&=\sqrt{(x-0)^2+(y-(-2))^2}\\\\ &=\sqrt{x^2+(y+2)^2}\end{aligned}

So sum of the two distances must be 6. Therefore:

d_1+d_2=6

Now, by substitution:

(\sqrt{x^2+(y-2)^2})+(\sqrt{x^2+(y+2)^2})=6

Simplify. We can subtract the second term from the left:

\sqrt{x^2+(y-2)^2}=6-\sqrt{x^2+(y+2)^2}

Square both sides:

(x^2+(y-2)^2)=36-12\sqrt{x^2+(y+2)^2}+(x^2+(y+2)^2)

We can cancel the x² terms and continue squaring:

y^2-4y+4=36-12\sqrt{x^2+(y+2)^2}+y^2+4y+4

We can cancel the y² and 4 from both sides. We can also subtract 4y from both sides. This leaves us with:

-8y=36-12\sqrt{x^2+(y+2)^2}

We can divide both sides by -4:

2y=-9+3\sqrt{x^2+(y+2)^2}

Adding 9 to both sides yields:

2y+9=3\sqrt{x^2+(y+2)^2}

And, we will square both sides one final time.

4y^2+36y+81=9(x^2+(y^2+4y+4))

Distribute:

4y^2+36y+81=9x^2+9y^2+36y+36

The 36y will cancel. So:

4y^2+81=9x^2+9y^2+36

Subtracting 4y² and 36 from both sides yields:

9x^2+5y^2=45

And dividing both sides by 45 produces:

\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1

Therefore, the equation for the locus of a point such that the sum of its distance to (0, 2) and (0, -2) is 6 is given by a vertical ellipse with a major axis length of 3 and a minor axis length of √5, centered on the origin.

5 0
3 years ago
Read 2 more answers
Find the equation of the line passing<br> through the points (3,-2) and (4, 6).<br> y = 8x + [?]
Sauron [17]

Step-by-step explanation:

1.) Plug in one of the points.

y = 8x + b

6 = 8(4) + b

2.) Solve for b (or [?])

6 = 32 + b \\  - 32 \:   \:  \:  \:  \:  \:  \:  \:  \:  - 32

32 cancels out on the right side.

Subtract 32 from 6, which is -26

3.) -26 = b

4.) Check with other point:

-2 = 8(3) + b

-2 = 24 + b

Cancel out 24 on the right side: 24-24 = 0

-2 - 24 = -26

-26 = b

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3 years ago
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andrezito [222]
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Difficulty with Word Problems

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2 years ago
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