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3 years ago

(50pts + brainliest) Which postulate can be used to prove that △BCA and △DAC are congruent?

Mathematics

2 answers:

kirza4 [7]3 years ago

6 0

Not entirely sure if this is the right answer but angles BAC and ACD are the same because they are alternate angles. You can tell because of the parallel lines AB and CD they lie on. That could probably be how the triangles are congruent because they have the same angles... I’m just guessing

alexandr1967 [171]3 years ago

5 0

Answer:SAS

Step-by-step explanation:

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The denominator of a fraction is two more than the numerator. If both numerator and denominator are decreased by six, the simpli

ira [324]

Answer:

$\dfrac{40}{42}$

Step-by-step explanation:

Let the numerator of the fraction=x

Since the denominator of a fraction is two more than the numerator.

Denominator=x+2

The fraction is therefore:

$\dfrac{x}{x+2}$

If both numerator and denominator are decreased by six, the fraction becomes:

$\dfrac{x-6}{x+2-6}$

The simplified result is $\dfrac{17}{18}$

Therefore:

$\dfrac{x-6}{x+2-6}=\dfrac{17}{18}\\$Next, we solve for x\\Cross multiply\\18(x-6)=17(x+2-6)\\18(x-6)=17(x-4)\\Expand the bracket\\18x-108=17x-68\\Collect like terms\\18x-17x=-68+108\\x=40$

Substituting x=40 into the initial fraction

$\dfrac{x}{x+2}=\dfrac{40}{40+2}=\dfrac{40}{42}$

Therefore, the original fraction is $\dfrac{40}{42}$

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Answer:

Step-by-step explanation:

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garik1379 [7]

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Step-by-step explanation:

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shepuryov [24]

Answer:

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Step-by-step explanation:

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Murrr4er [49]

Answer:

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Step-by-step explanation:

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