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Marrrta [24]
3 years ago
14

What is the area of triangle ABC ? round to the nearest square unit ?

Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer: 33 square units

Step-by-step explanation:

Given: Sides lengths of the triangle : 16 units, 10 units, 8 units.

Heron's formula:-

\text{Area of triangle}=\sqrt{s(s-a)(s-b)(s-c)}, where s is the semiperter and a,b and c are the side-lengths of the triangle.

Let a=16 , b=10 and c=8

Then,

s=\dfrac{a+b+c}{2}=\dfrac{16+10+8}{2}=17

Using Heron's formula:-

\text{Area of triangle}=\sqrt{17(17-16)(17-10)(17-8)}\\\\\Rightarrow\ \text{Area of triangle}=\sqrt{1071}=32.7261363439\approx33\text{ square units}

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Answer:

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Step-by-step explanation:

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If side opposite of 90° [∆] = x, side opposite of 45° [∆] = x / √2 = x √ 2 / 2.

Given side AC is opposite of 90° [∆ABC] = 32 √ 2, side opposite of 45° [∆ABC] = 32 √ 2 / √ 2 = 32 which is AB or BC.

Since side BC is part of BCD.

Side opposite of 90° [∆BCD] = BC = 32.

Since x is opposite of 30° [∆BCD].

x = Side opposite of 90° [∆BCD] / 2 = 32 / 2 = 16.

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Answer:

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Step-by-step explanation:

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Answer:

\angle 4 = 115^{\circ}

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Step-by-step explanation:

Given

\angle 2 = 65^{\circ}

See attachment

Solving (a): \angle 4

To solve for \angle 4, we make use of:

\angle 2 +\angle 4 = 180^{\circ}

The relationship between both angles is that they are complementary angles

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