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Studentka2010 [4]
3 years ago
14

Write the equation of a line with a slope of 7 and a y-intercept of -3. Put the equation in slope-intercept form.

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

y=7x-3

Step-by-step explanation:

y=mx+b

m is the slope, so replace m with 7

b is the t-intercept so replace b with the -3.

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GalinKa [24]
-2 is the y-intercept
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3 0
3 years ago
The time required to finish a test is normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. Wha
valkas [14]
The answer is 0.3413 because Explanation:

<span>z=<span><span>x−u</span>σ</span></span>, where <span>u=6 0andσ=10</span>.

Therefore the probability student finish the test between 50 to 60 minutes is,

<span>P<span>(50≤x≤60)</span>=P<span>(<span><span>50−60</span>10</span>≤z≤<span><span>60−60</span>10</span>)</span></span>

<span>P<span>(−1≤z≤0)</span>=P<span>(z≤0)</span>−P<span>(z≤−1)</span></span>

<span>=0.5000−0.1587=<span>0.3413</span></span>

3 0
3 years ago
Find an equation for the line perpendicular to y=-1/2x+4 and goes through the point (-1,10)
Artemon [7]

The slope of the perpendicular line will be 2. Remember, a perpendicular slope is the negative reciprocal.

So, we can make the equation y=2x+b. We need to find b, and put b in.

To find b, put in the numbers of y and x.

10=2(-1)+b

Solve for b:

10=-2+b\\b=10+2\\b=12

Now replace b in the original equation with 12 and that will be the answer:

The answer is y=2x+12.

5 0
3 years ago
A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

   = 59.43

B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
2 years ago
Please help:(( no links please!!
Usimov [2.4K]

Answer:

A :

B : Trapezius!

............

6 0
3 years ago
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