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lesantik [10]
3 years ago
11

How many different ways can 50 players in a marching band be arranged in rectangle arrangement?

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
6 0
Since the band has to be arranged in a rectangle arrangement, the way in which the players are going to be organized are going to be factors of 50. 
1st way: 1 by 50
2nd way: 2 by 25
3rd way: 5 by 10

Hope this helped!!
PilotLPTM [1.2K]3 years ago
4 0
1*50
2*25
5*50
You can basically do any number that can go in 50
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Using the slope formula for the points (1,5) and (2,-2), what would the denominator be?
suter [353]

Answer:

-7

Step-by-step explanation:

The slope formula is (y1 - y2) / (x1 - x2).

In this question we have two points: (1,5) and (2,-2).

x1 = 1

y1 = 5

x2 = 2

y2 = -2

then, plug in these numbers into the slope formula

(5-(-2))/(1-2) = 7 / -1 = -7

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3 years ago
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3 years ago
Use the discriminant to determine the number and type of solutions for the following equation. 12x2 + 10x + 5 = 0
Paul [167]
Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:

D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square)  two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0

Answer is: 
<span>A two irrational solutions </span>
4 0
4 years ago
Read 2 more answers
Sally has two coins. The first coin is a fair coin and the second coin is biased. The biased coin comes up heads with probabilit
coldgirl [10]

Answer:

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Step-by-step explanation:

''What is the probability that she selected the biased coin?”

When we have n possible outcomes of an event and all of them have the same probability of appearance, then in theory each possibility has a probability 1/n of being the result of the event.

In this case the event is choosing randomly a coin out of 2, so no matter what the biased coin is or the results we get when we toss it, the probability of choosing the biased coin is ½ = 0.5 or 50%.

4 0
3 years ago
(b) Find z such that 39% of all observations from a standard normal distribution are greater than z. (Enter your answer rounded
vova2212 [387]

For 39% of all observations that are greater than z on the normal distribution table, the percentage of observations that are lesser than z is

100 - 39 = 61%

The proportion is 61/100 = 0.61

From the normal distribution table, the value of z corresponding to this proportion is 0.28

Thus, the required value of z is 0.28

3 0
1 year ago
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