I would say that the answer is c because with the math done in 27 weeks you wouldve earned 1,485
Answer:
Step-by-step explanation:
given that the U.S. Department of Housing and Urban Development (HUD) uses the median to report the average price of a home in the United States.
We know that mean, median and mode are measures of central tendency.
Mean is the average of all the prices while median is the middle entry when arranged in ascending order.
Mean has the disadvantage of showing undue figure if extreme entries are there. i.e. outlier affect mean.
Suppose a price goes extremely high, then mean will fluctuate more than median.
So median using gives a reliable estimate since median gives the middle price and equally spread to other sides.
Lowest Common Denominator refers to lowes t common multiple. These expressions have two terms 'x' and 'y' and we want to choose the expression that has the highest power such that the other expressions can be multiplied into the common denominator.
For the 'x' term, the highest power is x⁴ and for the 'y' term, the highest power is y⁵
Common denominator of A, B, C, and D: x⁴y⁵
20y+5x≤100 divide all terms by 5
4y+x≤20 subtract x from both sides
4y≤-x+20 divide both side by 4
y≤-0.25x+5
So just in simplest terms, the slope is slightly negative and it should be shaded under the line since y is less than the line...so it is the second graph.
Answer and Step-by-step explanation: P(X) calculated by the binomial probability formula is:
P(X) = ![\left[\begin{array}{ccc}n\\X\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%5C%5CX%5Cend%7Barray%7D%5Cright%5D)
.
P(20) = ![\left[\begin{array}{ccc}53\\20\end{array}\right] .(0.3)^{20}.(1-0.3)^{33}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D53%5C%5C20%5Cend%7Barray%7D%5Cright%5D%20.%280.3%29%5E%7B20%7D.%281-0.3%29%5E%7B33%7D)
P(20) = 
P(20) = 0.0552
To determine whether the normal distribution can be used to estimate this probability, both n.p and n.(1-p) must be greater than 5:
n . p = 53*0.3 = 15.9
n.(1-p) = 53(1-0.3) = 37.1
Since both ARE greater than 5, normal distribution can be used.
To approximate:
mean = n . p = 15.9
standard deviation = 
= 3.34
Find the z-score:
z = 
= 
z-score = 0.8907
Comparing values:
0.8907 - 0.0552 = 0.8355
