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mylen [45]
2 years ago
14

(-1)×(-2)×10=? (this is integers)​

Mathematics
1 answer:
VLD [36.1K]2 years ago
8 0

Answer:the first one

Step-by-step explanation:

i am teacher lol

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Subtract and simplify.<br><br> (2y + 14.6m + 3.8) – (34.8m + 15.6 + 2y)
irina1246 [14]

Answer:

-20,2m-11,8

Step-by-step explanation:

rewrite it

2y+14,6m+3,8-(34,8m+15,6-2y)

remove the opposites

and then simplify

-20,2m-11,8

im not sure if this makes sense

5 0
2 years ago
Read 2 more answers
Help pls fast
Andrews [41]

Answer:

32.40cm²

Step-by-step explanation:

Given the parallelogram ABCD ;

side AB is always Parallel to CD, hence ;

AB = CD = 7.2cm

Perpendicular from C on AB is the height of the parallelogram = 4.5cm

Area of a parallelogram : base * height

Area of a parallelogram = length base * height

Area of a parallelogram = 7.2 cm * 4.5cm

Area of parallelogram = 32.40cm²

6 0
3 years ago
A taxi company manager is trying to decide whether the use of radial tires instead of regular belted tires improves fuel economy
siniylev [52]

Answer:

Step-by-step explanation:

Corresponding gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used form matched pairs.

The data for the test are the differences between the gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used.

μd = the gasoline consumption when radial tires is used minus the gasoline consumption when regular belted tires is used.

For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

The resulting p-value was .0152.

Since alpha, 0.05 > than the p value, 0.0152, then we would reject the null hypothesis. Therefore, at 5% significance level, we can conclude that the gasoline consumption when regular belted tires is used is higher than the gasoline consumption when radial tires is used.

7 0
3 years ago
Can i please get some (help on my maths)
quester [9]
ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}


We\ have:\\\\15x^2+7x-12=0\\\\a=15;\ b=7;\ c=-12\\\\substitute\\\\x_1=\dfrac{-7-\sqrt{7^2-4\cdot15\cdot(-12)}}{2\cdot15}=\dfrac{-7-\sqrt{49-5(15)(-12)}}{30}\\\\x_2=\dfrac{-7+\sqrt{49-4(15)(-12)}}{30}

First option.
5 0
3 years ago
The volume of a cube is 27 cubic inches. What is the length of an edge? Explain.
Lilit [14]

Answer:

<h2>3 in</h2>

Step-by-step explanation:

The formula of a volume of a cube:

V=a^3

a - length of an edge

We have V = 27 in³. Substitute:

a^3=27\to a=\sqrt[3]{27}\\\\a=3\ in

7 0
3 years ago
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