first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cboxed%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B-2%7D%7B%20h%7D%2C%5Cstackrel%7B2%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5C%5C%20y%3D%2B1%5Bx-%28-2%29%5D%5E2%2B2%5Cimplies%20y%3D%28x%2B2%29%5E2%2B2%20)
Answer:
(1, 3)
Step-by-step explanation:
x - 3y = -8
3x + y = 6
Isolate a variable in one of the equations:
y = 6 - 3x
Substitute the value of y into the other equation:
x - 3(6 - 3x) = -8
Use distributive property:
x - 18 + 9x = -8
Combine like terms:
10x - 18 = -8
Isolate the variable:
10x = 10
x = 1
Substitute the value of x into any equation:
3(1) + y = 6
3 + y = 6
Isolate the variable:
y = 3
Answer:
the answqee is D.
Step-by-step explanation:
Answer:
216
Step-by-step explanation:
Answer:
22
Step-by-step explanation:
<h2>
—Math</h2>
√(x+3) –4 = 1
√(x+3) = 1 +4
√(x+3) = 5
x + 3 = 5²
x = 25 –3
x = 22
