50 (1/3) mph
47 (1/2) = 47.5 mph
47.5 / 50 (1/3) =
<span>
<span>
<span>
0.943708609271523
</span>
</span>
</span>
hours
times 60 =
<span>
<span>
<span>
56.6225165563
</span>
</span>
</span>
minutes =
56 minutes <span><span><span>37.3509933775
</span>
seconds
</span></span>
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
---------------
The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
The problem is already in standard form but to get it into slope intercept form you rewrite the equation so it looks like
6y=-5x+7 divide all by 6
y=-5/6x+7/6
slope being -5/6 and b being 7/6
Answer:
C
Step-by-step explanation:
3/4/2/5 = 3*5/4*2
= 15 / 8
Answer: c) increase
Step-by-step explanation:
- A sample is a finite subset of the entire population on which research statistical test regarding his/ her objective .
As the sample size increases it comes closer to the population size, and so converge to a better result of researcher's analysis.
It means the size of the sample is proportional to the power of their statistical tests.
∴ As the size of the sample increases the power of statistical test increases.
Hence, If a research team increases the sample size for a study, the power of their statistical tests will <u>increases</u>.
Therefore , the correct answer is : c) increase
