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Nookie1986 [14]
4 years ago
13

How can the numbers 3 7 12 2 make 11​

Mathematics
2 answers:
Gala2k [10]4 years ago
8 0

Answer:

Step-by-step explanation:

7/3+12-2=12.33

7/2+12-3=12.5

Afina-wow [57]4 years ago
3 0
3x7 is 21 - 12 = 9+2= 11
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Find the value of x that makes line m ll n
guapka [62]

Answer:

See below ↓

Step-by-step explanation:

14.

  • Between two lines m ║ n, the ∦ cuts through them forming two angles
  • As it forms a line, the sum of the angles is 180°
  • 3x + 47 + x + 7 = 180
  • 4x + 54 = 180
  • 4x = 126
  • x = 126/4 = 63/2 = 31.5

15.

  • Alternate exterior angles on a transversal are equal
  • 5x = 2x + 78
  • 3x = 78
  • x = 26
5 0
2 years ago
Maria spent 15 days traveling in South America how many hours did she’s been traveling in South America
exis [7]

Answer:

360 hours

Step-by-step explanation:

When trying to find the number of hours out of the number of days someone has been doing something, assuming that she spent all 15 days traveling with no rest, you just multiply however many days (In this case, 15 days) by 24 hours.

This gives us the equation 15 times 24, which then equals 360.

A way I check these is that I divide however many hours I got by 24 and make sure it equals our first number.

We get the equation 360 divided by 24, which does, in fact, equal 15.

3 0
3 years ago
Read 2 more answers
Which is equivalent to 4y-2x=16
ad-work [718]
X-intercept. y-intercept
4*0-2x=16. 4y-2*0=16
-2x+0=16. 4y-0=16
-0. -0. +0 +0
-2x. /-2 = 16/-2 4y/4 =16/4
x = -8. y = 4
(-8,0) (0,4)
4 0
3 years ago
point b on the ground is 5 cm from point E at the entrance to Ollie's house. He is 1.8 m tall and is standing at Point D, below
enot [183]

Point B on the ground is 5 cm from point E at the entrance to Ollie's house.

Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

The complete question is as follows:

Ollie has installed security lights on the side of his house that is activated by a  sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.

The objective of this information is:

  • To find angle CAB and;
  • Find the distance Ollie is from the entrance to his house when he first activates the sensor.

The diagrammatic representation of the information given is shown in the image attached below.

Using  cosine rule to determine angle CAB, we have:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}= \dfrac{CA}{Sin \hat {ABC}}}

Here:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}}

\mathbf{\dfrac{4.5}{Sin \hat {15^0}} = \dfrac{6}{Sin \hat {CAB}}}

\mathbf{Sin \hat {CAB} = \dfrac{Sin 15 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = \dfrac{0.2588 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = 0.3451}

∠CAB = Sin⁻¹ (0.3451)

∠CAB = 20.19⁰

From the diagram attached;

  • assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;          

Then, we can say:

∠CBD = ∠GBF

∠GBF = (CAB + ACB)      

(because the exterior angles of a Δ is the sum of the two interior angles.

∠GBF = 15° + 20.19°

∠GBF = 35.19°

Using the trigonometric function for the tangent of an angle.

\mathbf{Tan \theta = \dfrac{GF}{BF}}

\mathbf{Tan \ 35.19  = \dfrac{1.8 \ m }{BF}}

\mathbf{BF  = \dfrac{1.8 \ m }{Tan \ 35.19}}

\mathbf{BF  = \dfrac{1.8 \ m }{0.7052}}

BF = 2.55 m

Finally, the distance of Ollie║FE║ from the entrance of his bouse is:

= 5 - 2.55 m

= 2.45 m

Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

Learn more about exterior angles here:

8 0
3 years ago
You want to change your cell phone service. The new company charges $40 per month for cell phone use. There is a one-time start-
faltersainse [42]
25+40*t=c
T=time,c=cost over time
4 0
3 years ago
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