Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
So some quick tips for inequalities:
**What you do to one side you HAVE TO do it to the other 2**
**If you ever divide a negative number past the inequality signs, the signs FLIP!!**
(e.g. 2>-5x>25)
-2/5 <x < -5
I hope that this has helped!
Answer:
L = 38/W
Step-by-step explanation:
The area of a rectangle is computed by multiplying length by width. For length L and width W in inches, your rectangle has area ...
A = LW
38 = LW
Then the length can be found by dividing the equation by W:
L = 38/W
Answer:
3
Step-by-step explanation:
Rewrite the logarithmic notation to index notation.
4^x=64
Change 64 to index notation
ie 64 = 4^3
Since the base is the same(4) cancel them out
You remain with x = 3
Perimeter of a square: side length * 4, since squares have equal side lengths
Take 2x - 3 for the side length and plug it into the formula.
(2x - 3) * 4 can be rewritten as 4(2x - 3)
Distribute 4 inside the parentheses.
8x - 12 = perimeter of the square
