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Iteru [2.4K]
2 years ago
9

Plz Help more than one !!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
3 0

Answer:

The correct option is (b).

Step-by-step explanation:

We need to find the equivalent to -2(4-3x)+(5x-2)

Using the associative property,

-2(4-3x) = -2(4)+2(3x)

= -8+6x

So,

-2(4-3x)+(5x-2) = -8+6x +5x-2

taking like terms together,

-2(4-3x)+(5x-2) = 6x+5x-8-2

= 11x-10

The equivalent expression is equal to (11x-10).

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486 divided by 19 <br><br><br> i need the remainder with answer
Goshia [24]

Answer:

25 remainder 11

Step-by-step explanation:

used a calc

5 0
2 years ago
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At a high school the average grade for the first semester for all subjects was 79.3. Based on this mean , the principal conclude
svet-max [94.6K]

Answer:

That is incorrect. It would be appropriate if the median were 79.3, since the median is the value in the middle (when placing the data in order).

4 0
2 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

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Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
2 years ago
Answers for both boxes please ​
Neporo4naja [7]

Answer:

i think its -1

Step-by-step explanation:

sorry if im wrong

3 0
2 years ago
If angle P measures 60 degrees, what is the measure of angle C?<br> A)120<br> B)30<br> C)60
LenaWriter [7]

Answer:

Answer is 120

Step-by-step explanation:

7 0
3 years ago
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