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ratelena [41]
3 years ago
13

An analyst has a limit order outstanding on a stock. He argues that the probability that the order will execute before the close

of trading is 0.20. Thus, the odds for the order executing before the close of trading are _______.a. one in four b. one in fivec. four to one d. five to ond
Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

b. One in Five

Step-by-step explanation:

To calculate probability, we need to know the formula: \frac{Number of Expected outcomes}{Total Number of possible outcomes}

in this case the probability is given in its decimal form, which is = 0.20

∴ to be able to use our formula easily, we will need to convert the probability to its fraction form.

which is 0.20 = \frac{20}{100} (<em> to do this, just simply put a 1 under the decimal point and replace the remaining values of 20 with zeroes)</em>

reducing \frac{20}{100} to its simplest form gives \frac{1}{5}.

Hence, relating it to our formula, we can see that the number of possible out comes is = 1

and the total number of outcomes = 5.

This means that the probability that the order will execute before the same of closing is the same as  1 in 5

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The solution to given system of equations y = 3x - 9 and y = -2x + 16 are (x, y) = (5, 6)

The solution to given system of equations y = 5x + 22 and -6x - 4y = -10 are (x, y) = (-3, 7)

<em><u>Solution:</u></em>

Given that, we have to solve each system by substitution method

<em><u>Given system of equations are:</u></em>

y = 3x - 9 ----------- eqn 1

y = -2x + 16 -------- eqn 2

Substitution method is done by substituting eqn 2 in eqn 1

<em><u>Substitute the value of "y" from eqn 2 into eqn 1</u></em>

-2x + 16 = 3x - 9

Move the variables to one side and constants to other side

-2x - 3x = -9 - 16

Combine the like terms

-5x = -25

Cancel the negative sign on both sides of equation

5x = 25

x = \frac{25}{5} = 5

<h3>x = 5</h3>

<em><u>Substitute x = 5 in eqn 1</u></em>

y = 3(5) - 9

y = 15 - 9

<h3>y = 6</h3>

Thus solution to given system of equations are (x, y) = (5, 6)

<em><u>Given another system of equations are:</u></em>

y = 5x + 22 ----- eqn 1

-6x - 4y = -10 ------ eqn 2

Substitute eqn 1 in eqn 2

-6x - 4(5x + 22) = -10

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Move the variables to one side and constants to other side

-26x = -10 + 88

-26x = 78

<h3>x = -3</h3>

Substitute x = -3 in eqn 1

y = 5( - 3) + 22

y = -15 + 22

<h3>y = 7</h3>

Thus solution to given system of equations are (x, y) = (-3, 7)

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