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3 years ago

5

Pls help me!!!! Im stuck!!!

2 answers:

blondinia [14]3 years ago

8 0

Answer:

infinite solutions

Step-by-step explanation:

you can solve this by the elimination method. take the rover a equation and multiply it by -7 and then combine the equations. when you do this, you can see that either side equals 0 which means that there are infinite solutions.

-7(y= 1.5x - 6) which equals the equation below

-7y= -10.5x-42 then combine the other equation

7y=10.5x+42 and that equals

0=0

exis [7]3 years ago

3 0

Answer:

has no solution.

Step-by-step explanation:

you can see that the two equations are almost identical except for the fact that one is multiplied by 7, but it isnt completely multiplied correctly so there would be no solutions.

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Read 2 more answers

Which of the following is the result of the equation below after completing the square and factoring?

Tems11 [23]

Answer:

D) $(x + \frac{5}{2})^{2} = \frac{9}{4}$

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation

<em> x² + 5 x + 8 = 4</em>

⇒ $x^{2} + 2 X \frac{5}{2} x + (\frac{5}{2} )^{2} - (\frac{5}{2} )^{2}+ 8 = 4$

<u><em>Step(ii):</em></u>-

By using (a + b)² = a² + 2 a b + b²

⇒ $(x + \frac{5}{2})^{2} - (\frac{5}{2} )^{2}+ 8 = 4$

⇒ $(x + \frac{5}{2})^{2} = 4 + (\frac{5}{2} )^{2} -8$

⇒ $(x + \frac{5}{2})^{2} = (\frac{25}{4} ) -4$

⇒ $(x + \frac{5}{2})^{2} = (\frac{25-16}{4} )$

⇒ $(x + \frac{5}{2})^{2} = \frac{9}{4}$

<u><em>Final answer:-</em></u>

$(x + \frac{5}{2})^{2} = \frac{9}{4}$

7 0

3 years ago