For the 60°'s topmost line, you can find the angle next to it is 120° because it's a straight line. You can do the same for 95° if you put that the angle opposite it is equal already because it's the opposite angle, so you subtract from 180° again to get 85°. When you extend the lines, you can find the alternate interior angles to the 60° and 85°, which are congruent to them. You then get that for both the formed triangles there is one 85° and one 60°, which together with one more angle should equal 180°. Through knowing that the sun of the triangles angles should be 180°, if you subtract the sum of 60° and 85° from 180°, you get the angle of the 3rd angle in the triangles (35°). This angle also forms 180° with x on a line, so 180°-35°=x, which is 145° seemingly.
The value of y will stretch into infinity and negative infinity. This is due to the fact that the line must always stay on the value of x = 60, therefore creating a vertical line on a graph that will result in an infinite amount of values of y.
Sum of angles in a triangle is 180 degrees.
2x + 2x + 8x = 180
12x = 180
x = 180/12 = 15
Therefore, the smallest angle mmeasures 2(15) = 30 degrees.
Answer:

Step-by-step explanation:
Given: 
To convert: the given sum into product
Solution:
Use formula: 
![cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]](https://tex.z-dn.net/?f=cosx%20%2B%20cos3x%20%2B%20cos5x%20%2B%20cos7x%3D2%5Ccos%20%5Cleft%20%28%20%5Cfrac%7Bx%2B3x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7Bx-3x%7D%7B2%7D%20%5Cright%20%29%2B2%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B5x%2B7x%7D%7B2%7D%20%5Cright%20%29%5Ccos%20%5Cleft%20%28%20%5Cfrac%7B5x-7x%7D%7B2%7D%20%5Cright%20%29%5C%5C%3D2%5Ccos%20%282x%29%5Ccos%20%28-x%29%2B2%5Ccos%20%286x%29%5Ccos%20%28-x%29%5C%5C%3D2%5Ccos%20%282x%29%5Ccos%20%28x%29%2B2%5Ccos%20%286x%29%5Ccos%20%28x%29%5C%5C%3D2%5Ccos%20x%5Cleft%20%5B%20%5Ccos%20%282x%29%2B%5Ccos%20%286x%29%20%5Cright%20%5D)
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