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AleksAgata [21]
3 years ago
11

Please answer fast need help

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

\fbox{y=3x-4}

Step-by-step explanation:

Let me know if you want the full explanation. Have a great day! ❤

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What is 2m×2 to the 7 power​
Nina [5.8K]

Answer:

256m

Step-by-step explanation:

not 100% sure but i hope this helps :)

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GEOMETRY SIDE LENGTHS​
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Answer:

I believe that the third answer is correct..... but I'm not positive.

Step-by-step explanation:

if you get the third side of the triangle to be 71 then it would go first. Then it would go to 45-55. And lastly to 71-45

3 0
3 years ago
What is the area of a circle with a radius of 22 feet? Use \piπ= 3.14 and round your answer to the nearest tenth.
Alex17521 [72]
The correct answer 1519.8 feet^2
6 0
3 years ago
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A line segment has endpoints at (–1, 4) and (4, 1). Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4
katrin2010 [14]

Answer:- A reflection of the line segment across the line y = –x .


Explanation:-

A reflection over the line y = -x, the x-coordinate and y-coordinate interchange their places and they are negated (the signs are changed).

Given :- A line segment has endpoints at (–1, 4) and (4, 1) such that it reflects produce an image with endpoints at (–4, 1) and (–1, –4).

(-1, 4)→(-4, 1) and

(4, 1)→(-1, -4)

Thus this shows a reflection of the line segment across the line y = –x.

4 0
3 years ago
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let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep
Nutka1998 [239]

Answer with Step-by-step explanation:

We are given that

x_1,x_2 and x_3 are linearly independent.

By definition of linear independent there exits three scalar a_1,a_2 and a_3 such that

a_1x_1+a_2x_2+a_3x_3=0

Where a_1=a_2=a_3=0

y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1

We have to prove that y_1,y_2 and y_3 are linearly independent.

Let b_1,b_2 and b_3 such that

b_1y_1+b_2y_2+b_3y_3=0

b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0

b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0

(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0

b_1+b_3=0

b_1=-b_3...(1)

b_1+b_2=0

b_1=-b_2..(2)

b_2+b_3=0

b_2=-b_3..(3)

Because x_1,x_2 and x_3 are linearly independent.

From equation (1) and (3)

b_1=b_2...(4)

Adding equation (2) and (4)

2b_1==0

b_1=0

From equation (1) and (2)

b_3=0,b_2=0,b_3=0

Hence, y_1,y_2 and y_3 area linearly independent.

5 0
3 years ago
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