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3 years ago

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3. Choose the best statistical question about lizards. O How many lizards do you have in your backyard? О What are the lengths o

f the lizards in your backyard? O How many bugs did a lizard eat today?

1 answer:

ASHA 777 [7]3 years ago

4 0

Answer: what are lengths of lizard

Step-by-step explanation: you can calculate average length of lizard

And also standard deviation and determine median too

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describe how the location of the vertex of the angle determines the process of finding the angle measures associated with that a

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Step-by-step explanation:

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3 years ago

Factor (7x^2 + 30x - 25)

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Factored form: (x-5)(7x+5) ☺

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2 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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2 years ago

Read 2 more answers

What is the m∠N ? Can someone help me :)

Sauron [17]

Answer:

<h2>61°</h2>

Step-by-step explanation:

Use the sine law:

$\dfrac{MO}{\sin(\angle N)}=\dfrac{NM}{\sin(\angle O)}$

We have:

$MO=18\\\\NM=6\\\\m\angle O=17^o\to\sin17^o\approx0.2924$

Substitute:

$\dfrac{18}{\sin(\angle N)}=\dfrac{6}{0.2924}$ <em>cross multiply</em>

$6\sin(\angle N)=(18)(0.2924)$

$6\sin(\angle N)=5.2632$ <em>divide both sides by 6</em>

$\sin(\angle N)=0.8772\to m\angle N\approx61^o$

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3 years ago

In the coordinate plane, the directed line segment from K to N has endpoints at K(–6, –2) and N(8, 3). Point L partitions the di

Dafna1 [17]

its c .i just took it

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3 years ago

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