5/4
rise/run
rise 5
run(across) 4
Answer:
x = 4
Step-by-step explanation:
Answer:
14m
Step-by-step explanation:
Step1:
<u>C</u><u>onsider the first right angled triangle using Pythagoras Theorem:</u>
(hyponenus)^2 = (opposite)^2 + (adjacent)^2
20^2 = 12^2 + A^2
A^2 = 400 - 144 = 256
A = Square root of 256 = 16m
Step2:
<u>CONSIDER THE SECOND RIGHT_ ANGLED TR</u><u>I</u><u>A</u><u>N</u><u>G</u><u>L</u><u>E</u><u>:</u>
<u>a</u><u>d</u><u>j</u><u>a</u><u>c</u><u>e</u><u>n</u><u>t</u><u>=</u><u>2</u><u>4</u><u>-</u><u>1</u><u>6</u><u>=</u><u>8</u><u>m</u>
<u>o</u><u>p</u><u>p</u><u>o</u><u>s</u><u>i</u><u>t</u><u>e</u><u>=</u><u>1</u><u>2</u><u>m</u>
Hypotenus=?
<u>(hypo</u><u>t</u><u>enus)^2 = (opposite)^2 + (adjacent)^2</u>
<u>H</u><u>^</u><u>2</u><u>=</u><u>1</u><u>2</u><u>^</u><u>2</u><u>+</u><u>8</u><u>^</u><u>2</u><u>=</u>
<u>1</u><u>4</u><u>4</u><u>+</u><u>6</u><u>4</u>
<u>H</u><u>^</u><u>2</u><u>=</u><u>2</u><u>0</u><u>8</u>
<u>H</u><u>=</u><u>s</u><u>q</u><u>u</u><u>a</u><u>r</u><u>e</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>2</u><u>0</u><u>8</u><u>=</u><u>1</u><u>4</u><u>.</u><u>4</u><u>2</u><u>m</u>
<u>T</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>e</u><u>a</u><u>r</u><u>e</u><u>s</u><u>t</u><u> </u><u>m</u><u>e</u><u>t</u><u>e</u><u>r</u><u>=</u><u>1</u><u>4</u><u>m</u>
<u>H</u><u>o</u><u>p</u><u>e</u><u> </u><u>i</u><u>t</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>s</u><u>.</u>
Answer:
A. and C. neither of them have a repeating y value if you input a vertical line on the graph
Subtract <span>x</span> from both sides
<span>5=2x−x
</span> Simplify <span><span>2</span><span>−x</span></span> to <span>x</span>
<span>5=x
</span>Switch sides
<span><span>x=5.</span></span>