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Umnica [9.8K]
3 years ago
13

The measured length of an arc as a distance is the definition of what?

Mathematics
1 answer:
igomit [66]3 years ago
7 0

Answer:

The arc length is the measure of the distance along the curved line making up the arc. It is longer than the straight line distance between its endpoints (which would be a chord)

Step-by-step explanation:

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Speed equal to 2 x square is equal to 10 X and Y is equal to 10 Y then find PTR 100​
mafiozo [28]
2x-10x=y-10y I’m not sure if you want to use this but yeah lol
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David earns a base rate of $12 an hour and receives a weekly attendance award of $20. he works 40 hours this week. what would be
Pavel [41]
20+12x
20+12(40)
20+480
500
total compensation for this week = $500
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3 years ago
Read 2 more answers
Please answer. find volume. thanks!
aivan3 [116]

Answer:

VOLUME = L X W X H AND THAT EQUALS TO 250 1/2

Step-by-step explanation:

3 0
1 year ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
Find the area of the rectangle.<br> (8x + 5) yards<br> (8x - 5) yards
Zepler [3.9K]

Answer:

48x-5

Step-by-step explanation:

multiply

5*8x

to get

8x+40x-5

combine like term

48x-5

7 0
2 years ago
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