Answer:
0 property
Step-by-step explanation:
I think so
Answer:
<h2>x² - 14x - 15 = (x − 7)² − 64</h2><h2>Then the coordinates of the vertex are (7 , -64)</h2>
Step-by-step explanation:
x² - 14x - 15 = x² - 14x + (49 - 49) - 15
= (x² - 14x + 49) - 49 - 15
= (x² - 14x + 7²) - 49 - 15
= (x − 7)² − (49 + 15)
= (x − 7)² − 64
x² - 14x - 15 = (x − 7)² − 64
Then the coordinates of the vertex are (7 , -64)
Well there is 20, 28,32,36,40, and 44. I think there are some more but those are the ones I could come up with.
Well there are 2 imaginary roots, if you are given 4 + i the conjugate is also a root 4 - i
these roots come in pairs sometimes written
<span>x=4±i</span><span>
you are told 2 roots are real, -2, 2
a degree 5 polynomial has 5 roots....
so since imaginary roots come in pairs, the 5th root has to be real...
hope that helps</span>
53 is the answer to your problem
