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melisa1 [442]
3 years ago
13

Point Q is located at (-4, 6). Point R is located at (8, 6).

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Step-by-step explanation:

Hi there!

Given;

Point Q is located at (-4, 6). Point R is located at (8, 6).

Note: Use distance formula.

Now;

(d) =  \sqrt{( {x2 - x1)}^{2}  + ( {y2 - y1)}^{2} }

Keep all values;

(d) =  \sqrt{ {(8 + 4)}^{2} + ( {6 - 6)}^{2}  }

Simplify;

(d) =  \sqrt{( {12)}^{2} }

Therefore, the distance is 12 units.

<u>Hope</u><u> it</u><u> helps</u><u>!</u>

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The mean temperature for the first 7 days in January was 6 °C.
balandron [24]

Answer:

6.875° C

the mean of a set of data is calculated using

mean =

For the first 7 days the mean is 8 and the count = 7

8 =  ( cross- multiply )

sum = 8 × 7 = 56

Add on the temperature on the 8 th day to the sum and divide by 8 for mean

sum = 56 - 1 = 55

mean =  = 6.875° C

2nd question

Height of marble from the ground

An independent variable is the variable in an experiment that you change to see if it has an effect on the dependent variable. In this case, Jack wanted to see whether the position of the marble on the ramp (which would be the height) has an effect on the kinetic and potential energy of the marble, then the height would be the independent because it is what is being changed.

The dependent would be the kinetic and potential energy and the constant would be the type of marble.

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3 years ago
If you can buy 1⁄3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars? Write your answer as a fractio
Stella [2.4K]
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Read 2 more answers
The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
Deffense [45]

Answer:

a

    f'(t) is  negative

b

 The  unit is degC/min

c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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