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sashaice [31]
3 years ago
7

Which table of values could be used to graph g(x), a reflection of f(x) across the x-axis?

Mathematics
2 answers:
Ede4ka [16]3 years ago
5 0

Reflecting a function across the x-axis means to change the sign of the function itself: you're mapping f(x)\mapsto -f(x)

So, if you have a x/y values table, you simply have to change sign to all the values in the y column.

lana [24]3 years ago
4 0

Answer:

option b

Step-by-step explanation:

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A. 208 in squared<br> B. 352 in squared <br> C. 136 in squared
bonufazy [111]
I think (A.) if not im so sorry
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8 0
3 years ago
What is square 192 in the simplest form
alexira [117]

sqrt(192)

sqrt( 16*12)

sqrt(16) * sqrt(12)

4 * sqrt(12)

4 * sqrt(4*3)

4 * sqrt(4) * sqrt(3)

4*2* sqrt(3)

8 sqrt(3)

8 0
3 years ago
Read 2 more answers
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0
3 years ago
There were 32 skaters at the rink on Friday. On Saturday, there were 27 skaters at the
shtirl [24]

Answer: 32 + 27 = 59

Step-by-step explanation:

5 0
3 years ago
Bobcat Park is a rectangular park with an area of 5 2/5 square miles.Its width is 1 11/25 miles.How long is the park?
ELEN [110]
I believe it is 3.75 miles. 5 2/5=5.4 and 1 11/25=1.44. 5.4/1.44=3.75.
4 0
3 years ago
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