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lidiya [134]
3 years ago
13

50 points

Mathematics
1 answer:
NISA [10]3 years ago
4 0
1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.
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Please help me?????/!!!!!!!!
hodyreva [135]
This is so easy okay just make sure if it’s true or not
7 0
3 years ago
ANSWER PLZ QUICK AND FAST WHAT THE ANSWER
ki77a [65]

48 + 42a < 132

42a < 84

A < 2

7 0
3 years ago
Hari earns Rs 4300 per month. He spends 80% from his income. How much amount does he save in a year? ​
Lelu [443]

Answer:

Hari saves $ 10,320 in a year.

Step-by-step explanation:

Given that Hari earns $ 4300 per month, and he spends 80% from his income, to determine how much amount does he save in a year, the following calculation must be performed:

100 - 80 = 20

4300 x 0.20 x 12 = X

860 x 12 = X

10320 = X

Therefore, Hari saves $ 10,320 in a year.

8 0
2 years ago
Using an ordered alphabet of 26 letters, how many ways are there to choose a set of six letters such that no two letters in the
mestny [16]
To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this - 
\binom {21} {6}= \frac{21*20*19*18*17*16}{6*5*4*3*2*1} =21*19*17*8=54264
Thus, the answer is that there are \boxed{54264} ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year! <em>2018</em>
5 0
3 years ago
2. The sum of two numbers is 30. Determine the two numbers if their product is a maximum.
SCORPION-xisa [38]

Answer:

X+y=30

X=30-y

Z=yx

Z=y(30-y)

D/dy

z=30–2y

At max 30–2y=0

2y=30 Y=15

Therefore x=15

Step-by-step explanation:

5 0
3 years ago
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