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3 years ago

50 points

Mathematics

1 answer:

NISA [10]3 years ago

4 0

1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.

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Write a real world situation that can be represented by the expression x - 12 subtraction

Tju [1.3M]

Ed has $37 and decides that he wants to go out to lunch with his friend Barb. They go out to eat, and when it comes time to pay the bill they decide to split it. It will cost Ed $12 to pay his half. How much money will he have left after he pays his share?

3 0

3 years ago

The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag

VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a p-value of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96\frac{2050}{\sqrt{49}} = 574$

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0

3 years ago

creativ13 [48]

Step-by-step explanation:

since the house, the school and the grocery store all have the same x coordinate (-4), they are on the same vertical line of x = -4.

and that means their distances are simply the differences in their y coordinates.

the only one different in that regard is the community center, but it is on the same y coordinate as the school, so the distance to the school is only the difference in their x coordinates.

so, the distance from house to school is

|5 - 3| = |3 - 5| = 2

as it is the same distance in either direction.

the distance from house to school to grocery store is the distance from house to school plus the distance from school to grocery store :

2 + |3 - -9| = 2 + |-9 - 3| = 2 + 12 = 14

now we need to find the distance from home to school to community center.

that is 2 + the distance from school to community center.

as mentioned above, since the school and the community center have the same y coordinate, their distance is the difference in their x coordinates :

|-4 - 6| = |6 - -4| = 10

so, in total the way house to school to community center is 2 + 10 = 12.

and that is shorter than the way house to school to grocery store, which is 14.

so, yes, the distance house to school to grocery store (14) is greater than the distance house to school to community center (12).

8 0

2 years ago

A detergent company periodically tests its products for variations in the fill weight. To do this, the company uses x-bar and R

maw [93]

Answer:

10.9361

Step-by-step explanation:

The lower control limit for xbar chart is

xdoublebar-A2(Rbar)

We are given that A2=0.308.

xdoublebar=sumxbar/k

Rbar=sumR/k

xbar R

5.8 0.42

6.1 0.38

16.02 0.08

15.95 0.15

16.12 0.42

6.18 0.23

5.87 0.36

16.2 0.4

Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8

Xdoublebar=88.24/8

Xdoublebar=11.03

Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8

Rbar=2.44/8

Rbar=0.305

The lower control limit for the x-bar chart is

LCL=xdoublebar-A2(Rbar)

LCL=11.03-0.308*0.305

LCL=11.03-0.0939

LCL=10.9361

8 0

3 years ago

You are drawing two cards, without replacement, from a standard deck of 52 cards. What is the

Serga [27]

Answer:

Dear student,

Answer to your query is provided below

Probability of drawing a 2 at first is (4/52) = (1/13)

Probability of drawing a face card in second try without replacement = 12/51

Step-by-step explanation:

Total no. Of cards = 52

Total no. Of cards of 2 = 4

Prob. Of drawing 2 = 4/52

Total no. Of face card = 12

Total no.of cards left in deck = 51

Prob. Of drawing face card = 12/51

5 0

3 years ago