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Rom4ik [11]
3 years ago
8

What conclusions can you draw from the distances that you recorded in question 7

Mathematics
2 answers:
Sauron [17]3 years ago
4 0

Answer:

If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line EF is a perpendicular bisector of the connecting line segments.

Step-by-step explanation:

PLATO

mezya [45]3 years ago
3 0

Answer:

If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line  is a perpendicular bisector of the connecting line segments.

Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
What is the equation of a circle with center (−8, 3) and radius 8?
Genrish500 [490]

Answer:

x^2 + y^2 + 16x + 6y + 9 = 0

Step-by-step explanation:

Using the formula for equation of a circle

(x - a)^2 + (y + b)^2 = r^2

(a, b) - the center

r - radius of the circle

Inserting the values given in the question

(-8,3) and r = 8

a - -8

b - 3

r - 8

[ x -(-8)]^2 + (y+3)^2 = 8^2

(x + 8)^2 + (y + 3)^2 = 8^2

Solving the brackets

( x + 8)(x + 8) + (y +3)(y+3) = 64

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Rearranging algebrally,.

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Bringing in 64, thereby changing the + sign to -

Therefore, the equation of the circle =

x^2 + y^2 + 16x + 6y + 9 = 0

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3 years ago
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