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4 years ago

What conclusions can you draw from the distances that you recorded in question 7

Mathematics

2 answers:

Sauron [17]4 years ago

4 0

Answer:

If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line EF is a perpendicular bisector of the connecting line segments.

Step-by-step explanation:

PLATO

mezya [45]4 years ago

3 0

Answer:

If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line is a perpendicular bisector of the connecting line segments.

Step-by-step explanation:

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What is 572 rounded to the nearest 10 and 100

Liula [17]

572 rounded to the nearest 10 is 570 and 572 rounded to nearest 100 is 600.

5 0

3 years ago

PLEASE HELP MEEEEeeee

Evgesh-ka [11]

Based on the graph shown, the intersection is (1.231, -0.452). 1.231 acts as coordinate x of the intersection, and -0.452 acts as coordinate y of the intersection.

In the equation
$\frac{1}{2}x-1.0675=3x-4.145$
the solution is the value of x. So the solution of the equation is the value of x. So, we use coordinate x of the intersection to find the solution of the equation, that is 1.231.

Final answer: 1.231

6 0

4 years ago

Read 2 more answers

Use multiplying by 1 to find an expression equivalent to 3/14 with a denominator of 14 y.

Soloha48 [4]

As a matter of simplification, same/same = 1.

now, "same" could be anything whatsoever, you name it, a whole polynomial, a whole anything whatsoever.

$\bf \cfrac{\sqrt{2}}{\sqrt{2}}=\cfrac{\sqrt{3}}{\sqrt{3}}=\cfrac{100000000}{100000000}=\cfrac{eggs}{eggs}=\cfrac{miles}{miles}=\cfrac{\frac{\quad \sqrt{3}}{\sqrt[5]{17}}\quad }{\frac{\sqrt{3}}{\sqrt[5]{17}}}=\cfrac{whatever}{whatever}=1$

now, that said, let us use 1 in this case then ... hmmmm we simply need a "y" in the denominator, so we simply multiply the denominator AND numerator by "y", y/y = 1 btw.

$\bf \cfrac{3}{14}\cdot \cfrac{y}{y}\implies \cfrac{3y}{14y}$

6 0

4 years ago

The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high,

Andrej [43]

Answer:

A. $18

B. $200

C. $p\in (16,20)$

Step-by-step explanation:

Function:

$f(p) = -50p^2 + 1,800p - 16,000$

<u>Parts A and B:</u>

The price that generates the maximum profit is ate vertex of parabola. Find the coordinates of the vertex:

$p_v=\dfrac{-b}{2a}=\dfrac{-1,800}{2\cdot (-50)}=\dfrac{1,800}{100}=18\\ \\f(p_v)=-50\cdot 18^2+1,800\cdot 18-16,000=200$

The price that generates the maximum profit is $18

The maximum profit is $200

The company breaks even when the profit is positive. From the graph of the function you can see that the graph of the function is over p-axis for all $p\in (16,20)$ , so the positive profit is for $p\in (16,20)$

In p=16 and p=20, the profit is 0 and when p<16 and p>20, there will be a loss.

7 0

4 years ago

Im sorry, im not good with negatives and positives xD this is the last one Which values satisfy the inequality? |x| < 3 Choos

Katarina [22]

No. You can't squirm out of it that easily ! Sorry.

The absolute value of a number is its size without a plus or minus.
So you don't need to be good with plus and minus to work absolute values.

The statement says "the absolute value of 'x' is less than 3".
Let's test each choice and see if it works:

a). x = -6. The absolute value of -6 is 6. Is that less than 3 ? No.

b). x = -5. The absolute value of -5 is 5. Is that less then 3 ? No.

c). x = -1. The absolute value of -1 is 1. Is that less than 3 ? Yes.

d). x = 2. The absolute value of 2 is 2. Is that less than 3 ? Yes.

Do you see ? You don't need to be Einstein or a math whiz
to answer this one.

You're just giving up because people say that girls can't do math,
and instead of telling them where to stick it, you bought into it.

8 0

4 years ago