Answer:
-6x - 8y + 20 = 0
Step-by-step explanation:
If you have two points (x₁; y₁) and (x₂; y₂), you can use the formula to find the equation of a straight line:
![\tt\boxed{\tt(y_1-y_2)x+(x_2-x_1)y+(x_1y_2-x_2y_1)=0}\\\\ \text{in your case:} \ x_1=6; \ x_2=-2; \ y_1=-2; \ y_2=4, \ \ so:\\\\(-2-4)x+(-2-6)y+(6\cdot4-(-2)(-2))=0\\\\-6x-8y+(24-4)=0\\\\-6x-8y+20=0](https://tex.z-dn.net/?f=%5Ctt%5Cboxed%7B%5Ctt%28y_1-y_2%29x%2B%28x_2-x_1%29y%2B%28x_1y_2-x_2y_1%29%3D0%7D%5C%5C%5C%5C%20%5Ctext%7Bin%20your%20case%3A%7D%20%5C%20x_1%3D6%3B%20%5C%20x_2%3D-2%3B%20%5C%20y_1%3D-2%3B%20%5C%20y_2%3D4%2C%20%5C%20%5C%20so%3A%5C%5C%5C%5C%28-2-4%29x%2B%28-2-6%29y%2B%286%5Ccdot4-%28-2%29%28-2%29%29%3D0%5C%5C%5C%5C-6x-8y%2B%2824-4%29%3D0%5C%5C%5C%5C-6x-8y%2B20%3D0)
Answer:
10 ft, 14 ft
Step-by-step explanation:
Let b represent the length of the shorter base. Then the longer one is b+4 and the area is ...
A = (1/2)(b1 +b2)h
120 = (1/2)(b +(b+4))(10) . . . . use given values
12 = b+2 . . . . . . divide by 10, simplify
10 = b
14 = b+4
The measurements of the two bases are 10 ft and 14 ft.
14:7
42:21
6:3
24:12
Hope this helps!
<span>-2 inches
This is a simple average of 8 data points. All you need to do is add the value of all the data points together, then divide the sum by the number of data points. So
(â’4 + â’6 + â’3 + â’1 + 0 + 2 + â’1 + â’3) / 8 = -16 / 8 = -2
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