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valentina_108 [34]
3 years ago
7

In Which Quadrant is this true

Mathematics
1 answer:
34kurt3 years ago
5 0

Given:

\sin \theta

\tan \theta

To find:

The quadrant in which \theta lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only \sin\theta and \csc\theta are positive.

In Quadrant III, only \tan\theta and \cot\theta are positive.

In Quadrant IV, only \cos\theta and \sec\theta are positive.

We have,

\sin \theta

\tan \theta

Here, \sin\theta is negative and \tan\theta is also negative. It is possible, if \theta lies in the Quadrant IV.

Therefore, the correct option is D.

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what is the value of x in the diagram below? if necessary round your answer to the nearest tenth of a until
VladimirAG [237]

Answer:

C

Step-by-step explanation:

Calculate AC using Pythagoras' identity in ΔABC

AC² = 20² - 12² = 400 - 144 = 256, hence

AC = \sqrt{256} = 16

Now find AD² from ΔACD and ΔABD

ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²

ΔABD → AD² = 12² - x² = 144 - x²

Equate both equations for AD², hence

256 - 400 + 40x - x² = 144 - x²

-144 + 40x - x² = 144 - x² ( add x² to both sides )

- 144 + 40x = 144 ( add 144 to both sides )

40x = 288 ( divide both sides by 40 )

x = 7.2 → C



6 0
3 years ago
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Help??????????????? Uh yeet
Rashid [163]

Answer:

C 117

Step-by-step explanation:

<2 = 63

<4 = <2  vertical angles

<4 + <7 = 180

63 + <7 = 180

subtract 63 from each side

<7 = 117


5 0
3 years ago
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Which term describes this figure?
Ann [662]
Hey there! :)

This figure is an irregular polygon. Regular polygons have side lengths that measure the same length. In this polygon, not all the sides are equal. Therefore, it is an irregular polygon.

Your answer is the 2nd choice ⇒ irregular polygon

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3 years ago
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Find the vertex for the equation: <br> y = 3x^2 + 18x + 30<br> (-3, 3)<br> (-3, -51)<br> (3, 111)
Papessa [141]
I think (-3, 3 ) !!!!!!!!!!!
8 0
3 years ago
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In the polynomial below, what number should replace the question mark to produce a difference of squares? x2 + ?x - 49
shutvik [7]
We are asked to find unknown or the missing number to complete the polynomial given in the problem which is x² + ?x -49. First, let us equate the number to be equal to zero such as it would become x² + ?x - 49 = 0. Next, we need to find the factors such that it would produce a difference of squares and these two factors are a = +7 and b = -7. Hence, the complete solution is shown below:
(x + 7) (x-7) = 0
perform distribution and multiplication of terms such as shown below:
x² + 7x - 7x - 49 = 0
Combine the same term such as we can either add or subtract +7x to -7x and the result will be equal to 0x.
 x² + 0x - 49 = 0

Therefore, the missing number is 0. The answer is 0 which will result to x² +0x - 49.
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3 years ago
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