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vichka [17]
3 years ago
9

As a science fair project, you want to launch an 950 g model rocket straight up and hit a horizontally moving target as it passe

s 33.0 m above the launch point. The rocket engine provides a constant thrust of 20.0 N . The target is approaching at a speed of 18.0 m/s .
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?

= 43.56m

Explanation:

acceleration =

(20 - (0.95 * 9.8) )/ (0.95)

= 10.68 / 0.95

= 11.24 m/s²

we use

s = ut + (1/2) at²

Given that

s= 40

u =0  

s = 0 * t + (1/2) (11.24)t²

t = √(66/1.24)

t = √5.87

t = 2.42sec

hence

Horizontal distance = 18 * 2.42

= 43.56m

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