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vichka [17]
3 years ago
9

As a science fair project, you want to launch an 950 g model rocket straight up and hit a horizontally moving target as it passe

s 33.0 m above the launch point. The rocket engine provides a constant thrust of 20.0 N . The target is approaching at a speed of 18.0 m/s .
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?

= 43.56m

Explanation:

acceleration =

(20 - (0.95 * 9.8) )/ (0.95)

= 10.68 / 0.95

= 11.24 m/s²

we use

s = ut + (1/2) at²

Given that

s= 40

u =0  

s = 0 * t + (1/2) (11.24)t²

t = √(66/1.24)

t = √5.87

t = 2.42sec

hence

Horizontal distance = 18 * 2.42

= 43.56m

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5 0
2 years ago
Explain why when landing on a firm surface after a fall you should not land with stiff legs.
Digiron [165]

While lending on a surface, we should bend our knees

to provide more time to the velocity change thus decresing the net force on the legs.

transfers a part of reactionary force to thick thigh and calf muscles whicch act as dampers absorbing a part of energy and provides cushioning effect.

Explanation:

We know that Force equal Mass times acceleration.

Acceleration equals the change in velocity per unit time. Hence if the time involved in velocity change is large, resultant acceleration would be less. Hence the resulting force would also be of less magnitude.

The above explanation owes to the act of bending of knees while jumping.

When we jump and simultaneously land, we fall with a force equalling “mass of our body * gravity”. Upon our landing, on the ground, the reactionary force is transmitted to our legs.

Considering our legs are stiff and straight, the force travels quickly through the bones and muscle without sufficient change in the velocity. Hence, we experience nearly the same force on our bones as a result of which bones some-times buckle.

A safer way to land is Landing while folding of the legs. By folding our legs, we give force extra time to travel through the bended section of knee bones. During the travel, the force interacts with thick thigh and calf muscles which act as dampers and absorbs some amount of force.  

By bending, we also increase the time thus decreasing acceleration, hence the force on legs. Thus, by the dual effect of increasing time and damping effect out legs are saved from the excessive buckling effect and remain safe.

6 0
4 years ago
How much work should be done to lift a 5kg brick to the height of 12m
Goshia [24]

Answer: 588 joules

Explanation:

Work is done when force is applied on an object over a distance ( whether vertical or horizontal). It is measured in joules.

Thus, Workdone = Force X distance

- Vertical distance to be moved by the brick = 12 metres

- Mass of box = 5kg

- Acceleration due to gravity when box was lifted represented by g is a constant with value of 9.8m/s^2

Now, recall that Force = Mass x acceleration due to gravity

i.e Force = 5kg x 9.8m/s^2

Force = 49 Newton

So, Workdone = Force X Distance

Workdone = 49 Newton X 12 metres

Workdone = 588 joules

Thus, 588 joules of work was done.

8 0
3 years ago
Read 2 more answers
Draw a wave that has a wavelength of 3 cm and an amplitude of 1 cm. Label the wavelength, the amplitude, the rest position, and
Minchanka [31]

Answer:

Please find attached, the required wave drawn with MS Excel

Explanation:

Functions that represent waves is given as follows

A general form of the wave equation is A·sin(B·x) + D

Where;

B = 2·π/T

T = The period of the wave = 1/f

D = The vertical shift of the wave = 0

A = The amplitude of the wave = 1 for sine wave

v = The wave velocity

λ = The wavelength of the wave

f = The frequency of the wave

v = f·λ

At constant <em>v</em>, λ ∝ 1/f  

∴ λ ∝ T

Where T = 3, we have;

B = 2·π/T

∴ B = 2·π/3

Therefore, we have the wave with an amplitude of 1 cm, and wavelength, 3 cm, given as follows

y = sin((2·π/3)·x)

Plotting the above wave with MS Excel, we can get the attached wave

4 0
3 years ago
A uniform beam XY is 100 cm long and weighs 4.0N.The beam rests on a pivot 60 cm from end X. A load of 8.0 N hangs from the beam
Alex777 [14]

Answer:

<h2>The magnitude of force F is 18N</h2>

Explanation:

The magnitude of the force in the set up can be solved for using the principle of moment. According to the principle, the sum of clockwise moment  is equal to the sum of anticlockwise moments.

Moment = Force * perpendicular distance

Clockwise moments;

The force that acts clockwise is the unknown Force F and 4N force. If the  beam rests on a pivot 60 cm from end X and a Force F acts on the beam 80 cm from end X, the perpendicular distance of the force F from the pivot is 80-60 = 20cm and the perpendicular distance of the 4N force from the pivot is 60-50 = 10cm

Moment of force F about the pivot = F * 20

Moment of 4N force about the pivot = 4*10 = 40Nm

Sum of clockwise moment = 40+20F...(1)

Anticlockwise moment;

The  8N will act anticlockwisely about the pivot.

The distance between the 8N force and the pivot is 60-10 = 50cm

Moment of the 8N force = 8*50

=400Nm...(1)

Equating 1 and 2 we have;

40+20F = 400

20F = 400-40

20F = 360

F = 18N

The magnitude of force F is 18N

6 0
4 years ago
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