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Lesechka [4]
3 years ago
13

Samuel applies a horizontal force of 35.0 N to a sleigh over a distance of 1.50 m along a level surface. Calculate the work done

on the sleigh by samuel. show your work.
Physics
1 answer:
Ronch [10]3 years ago
5 0

Answer:

52.5 J

Explanation:

Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.

i.e W = F × s

It is a scalar quantity and measured in Joules (J).

Given that: F = 35.0 N and s = 1.50 m, then;

W = F × s

W = 35.0 × 1.5

   = 52.5 J

Therefore, the work done on the sleigh by Samuel is 52.5 J.

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The magnitude of the unknown height of the projectile is determined as 16.1 m.

<h3>Magnitude of the height</h3>

The magnitude of the height of the projectile is calculated as follows;

H = u²sin²θ/2g

H = (36.6² x (sin 29)²)/(2 x 9.8)

H = 16.1 m

Thus, the magnitude of the unknown height of the projectile is determined as 16.1 m.

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A racecar driver steps on the gas, and his racecar travels 20 meters in 2 seconds starting from rest. The acceleration of the ra
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Answer:

2.5m/s^2

Explanation:

Step one:

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distance = 20meters

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velocity= 20/2

velocity= 10m/s

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divide both sides by 40

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An electric field is produced by the very long, uniformly charged rod drawn above. If the strength of the electric field is E1 a
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Answer: hello the complete question is attached below

answer :

r2 = 4r1

Explanation:

Electric field strength = F / q

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3 years ago
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