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professor190 [17]
3 years ago
10

Simplify the expression 22-50+2

Mathematics
2 answers:
Bad White [126]3 years ago
6 0

the answer is.....

-26

PSYCHO15rus [73]3 years ago
3 0

Answer:

=-26

Step-by-step explanation:

22-50 plus 2

hope this helped

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HELP ME PLEASE!! Word problem, what's wrong? explain.
dmitriy555 [2]

Answer:

She made a mistake in Step 7.

Step-by-step explanation:

Step 1 through 6 are correct. Only from Step 6 to Step 7 the problem comes in: both sides of the equation are multiplied by x, however the x on the left side, by error, becomes 1. The correct state in Step 7 should look like this:

x(\frac{1}{2}P-x)=256

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4 years ago
Find the slant height of this square pyramid
shutvik [7]
Lateral Surface Area of a square pyramid (4 isosceles triangles): For the isosceles triangle Area = (1/2)Base x Height. Our base is side length a and for this calculation our height for the triangle is slant height s. With 4 sides we need to multiply by 4. (hope this will help)
8 0
3 years ago
Read 2 more answers
2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.
likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

y = ^+_- \sqrt{-x^2+4x+4} -5

Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

\frac{52 ^+_-\sqrt{1664}}{26}

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0
3 years ago
Can someone please tell me if i am right?
pentagon [3]
Second one is correct, that is an identity.

Third one is a contradiction:
6x - 15 = 3 * (2x - 6)    ------>    6x - 15 = 6x - 18

Fourth one:
5x - 3 * (x - 4) = 2 * (x - 6) ---> 5x - 3x + 12 = 2x - 12 ---> 2x + 12 = 2x -12
So this is a contradiction as well.
4 0
3 years ago
Give the radian measure of an angle drawn in standard position that corresponds with the ray containing the coordinate point (−1
Sergeu [11.5K]

Answer:

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point (-12, -3\sqrt{2}) is approximately 1.108\pi radians.

Step-by-step explanation:

With respect to origin, the coordinate point belongs to the third quadrant, which comprises the family of angles from \pi\,rad to \frac{3\pi}{2}\,rad. The angle in standard position can be estimated by using the following equivalence:

\theta = \pi\,rad + \tan^{-1} \left(\frac{3\sqrt{2}}{12} \right)

\theta \approx \pi \,rad + 0.108\pi \,rad

\theta \approx 1.108\pi\,rad

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point (-12, -3\sqrt{2}) is approximately 1.108\pi radians.

5 0
3 years ago
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