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mihalych1998 [28]
3 years ago
7

What is the simplified expression for 5 to the power of negative 3 multiplied by 2 to the power of 2 multiplied by 5 to the powe

r of 6 whole over 2 to the power of 3 multiplied by 5 to the power of 2?

Mathematics
1 answer:
Anton [14]3 years ago
8 0
5/2 is the answer showed a picture look at pdf

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What best describes the asymptote of an exponential function of the form f(x)=b^x?
horrorfan [7]

It depends on the value of b


Exponential functions are defined for positive values of the base [ŧex] b [/tex]. Also, they're not defined if b=1, or at least let's say that this is a trivial case, since it is the constant function 1.


Case 0<b<1:

If the base sits between 0 and 1, the exponential function is constantly decreasing. The explanation is quite intuitive, assume for the sake of simpleness that b is rational. If it sits between 0 and 1, it means that it can be written as a fraction p/q, with p<q. So, if you give a large exponent to b, you obtain


\frac{p^x}{q^x},\quad p^x \ll q^x \text{ as } x \to \infty


On the other hand, if you consider negative exponents, you switch numerator and denominator and then raise to the same exponent the fraction q/p, which gets larger and larger.


So, if 0<b<1, we have


\lim_{x \to -\infty} b^x = \infty,\qquad \lim_{x \to \infty} b^x = 0


and thus 0 is a horizontal asymptote as x tends to (positive) infinity.


Case b>1:

This case is very similar, except all roles are inverted. Now you start with a fraction p/q where p>q. So, with positive, large exponents you get


\frac{p^x}{q^x},\quad p^x \gg q^x \text{ as } x \to \infty


And as before, negative exponents switch numerator and denominator, so the fraction becomes q/p and thus you have


\lim_{x \to -\infty} b^x = 0,\qquad \lim_{x \to \infty} b^x = \infty


So, again, 0 is a horizontal asymptote, but this time for x tending towards negative infinite.

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What's 1.625 rounded to the nearest hundreth
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1.63 is the answer. :))))))
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8. Find the slope. Make sure to reduce.
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I think the answer is: -3/7x
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Can someone please solve this?<br> a-3 Times a+7
Colt1911 [192]
You have to combine like terms.
Answer: -2a+7 

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3 years ago
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Is this right? I’m unsure if I’m doing this correctly. Thanks
gogolik [260]
The answer is 24 as it's the smallest number given that is divisible by both 6 and 8.
4 0
3 years ago
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