x = 3 + y Eqn(1)
y = -2x + 9 Eqn(2)
Let us solve the system of equations with the substitution method
x - 3 = y (Subtracting 3 from both sides of the Eqn(1))
Replacing y = x - 3 in Eqn (2), we have:
x - 3 = -2x + 9
x = -2x + 9 + 3 (Adding 3 to both sides of the equation)
x + 2x = 9 + 3 (Adding 2x to both sides of the equation)
3x = 12 ( Adding like terms)
x = 12/3 (Dividing by 3 on both sides of the equation)
x = 4
Replacing x=4 in Eqn(1), we have:
4 = 3 + y
4 - 3 = y (Subtracting 3 from both sides of the equation)
y=1
The answers are:
x= 4 and y=1
I think the equation for this would be 9+1.35x
then i think you would have to round it after because you cant really have a third of someone.
56 miles, The car traveled m miles during the first hour and m squared miles during the second hour. The ratio m/m squared = 1/7 and cross multiplying yields m squared = 7m, so m=7. This means that the total distance traveled was 7+7squared = 56 miles
Answer:
50.27 is the correct answer, at least should be
