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antoniya [11.8K]
2 years ago
13

HELP8 Prove that 8^6+4^11 is divisible by 17. Answer __*17

Mathematics
1 answer:
Marina CMI [18]2 years ago
8 0

Answer:

<u>262,144</u> goes in the blank

Step-by-step explanation:

8^6 = 262,144

4^11 = 4,194,304

4,194,304 + 262,144 = 4,456,448

4,456,448 ÷ 17 = 262,144

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Which is the graph of<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20-%202" id="TexFormula1" t
Anna11 [10]

ANSWER

See attachment.

EXPLANATION

The given function is

y =  \sqrt[3]{x + 1}  - 2

The parent function is

y =  \sqrt[3]{x}

When we shift the parent graph to the left one unit, and down 2 units, we obtain the graph of the given function.

The graph of this function is shown in the attachment.

5 0
3 years ago
Pls help I don't know how to do this​
AVprozaik [17]

Answer:

Vertex, I believe.

7 0
2 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
2 years ago
A figure has 4 sides. One pair of opposite sides are each 2 inches long. The other pair of opposite sides are each 5 inches long
matrenka [14]
Your answer is 14 inches.
5 0
2 years ago
Read 2 more answers
How do you solve and check x/4 = -5
Mashutka [201]

Rearrange x/4-(-5)=0

Simplify x/4

-5 = -5/1 = -5*4/4

x- (-5*4)/4 = x+20/4

x+ 20/4 = 0

x+20/4 * 4 = 0*4

The equation now takes the shape: x+20=0

subtract 20 from both sides of the equation: x=-20

Answer: x=-20

6 0
3 years ago
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