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3 years ago

8

Why do cell sometimes need to use active transport?

1 answer:

victus00 [196]3 years ago

5 0

Some Substance are moved by energy,some pass through diffusion

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PLEASE HELP!! DUE IN 40 MINUTES!!

Irina18 [472]

A frame of reference can be thought of as the state of motion of the observer of some event. For example, if you're sitting on a lawn chair watching a train travel past you ... you could even watch a glass of water sitting on a table inside the train move ... This seems like a simple and obvious example, yet when you take a step

6 0

3 years ago

A basketball has a mass of 609 g. Moving to the right and heading downward at an angle of 32° to the vertical, it hits the floor

andrezito [222]

Answer:1.549 kg-m/s

Explanation:

Given

mass of basketball =609 g

ball is moving downward right at an angle of $32 ^{\circ}$ with vertical

After hitting the floor it moves with a speed of 3 m/s

change in Momentum in x direction

$P_x=musin32\hat{i} -mvsin32\hat{i}$

where u=3m/s

v=3m/s

m=mass of ball

$P_x=0$

Change in momentum in Y-direction

$P_y=-mucos32\hat{j}-mvcos32\hat{j}=-2mvcos32$

$P_y=-1.549\hat{j} kg-m/s$

3 0

3 years ago

The engine of a locomotive exerts a constant force of 6.8 105 N to accelerate a train to 80 km/h. Determine the time (in min) ta

Setler [38]

Answer:

t = 6 minutes

Explanation:

Given that,

Force, $F=6.8\times 10^5\ N$

Initial speed of the train, u = 0

Final speed of the train, v = 80 km/h = 22.22 m/s

The mass of the train, $m=1.1\times 10^7\ kg$

We need to find the time taken by the train to come to rest. We know that,

F = ma

$F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{1.1\times10^7\times (22.22-0)}{6.8\times 10^5}\\\\t=359.44\ s$

or

t = 6 minutes (approx)

So, the required time is equal to 6 minutes.

3 0

3 years ago

LOOK AT THE PICTURE> PLEASE HELP NO LINKS AT ALL

kotegsom [21]

Answer: D

Explanation:

It is at organ level because the kidney is an organ

6 0

3 years ago

Suppose we want a satellite to revolve around the earth 5 times a day. What should be the radius of its orbit? (The mass of the

Lyrx [107]

To solve this exercise we must apply the concepts related to the balance of forces.

For this particular case the force caused on the satellite from the planet must be equivalent to the Centrifugal Force, that is

$F_g = F_c$

$\frac{GMm}{r^2} = m\omega^2 r$

Where,

G = Gravitational Universal Constant

M = Mass of earth

m = mass of satellite

r = Distance/Orbit

Using the concept of Period through the angular velocity we have,

$\frac{GM}{\omega^2} = r^3$

$\frac{GMT^2}{4\pi^2} = r^3$

Finally re-arrange the equation to find the orbit and replacing, we have,

$r^3 = \frac{6.67*10^{-11}*5.97*10^{24}}{4\pi^2}(\frac{24*3000}{5})^2$

$r^3 = 3.011*10^{21}$

$r = 1.44*10^7m$

Therefor the orbit would be 14400 kilometers

5 0

4 years ago