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vova2212 [387]
3 years ago
9

A basketball has a mass of 609 g. Moving to the right and heading downward at an angle of 32° to the vertical, it hits the floor

with a speed of 3 m/s and bounces up with nearly the same speed, again moving to the right at an angle of 32° to the vertical. What was the momentum change ? (Take the axis to be to the right and the axis to be up. Express your answer in vector form.)
Physics
1 answer:
andrezito [222]3 years ago
3 0

Answer:1.549 kg-m/s

Explanation:

Given

mass of basketball =609 g

ball is moving downward right at an angle of 32 ^{\circ} with vertical

After hitting the floor it moves with a speed of 3 m/s

change in Momentum in x direction

P_x=musin32\hat{i} -mvsin32\hat{i}

where u=3m/s

v=3m/s

m=mass of ball

P_x=0

Change in momentum in Y-direction

P_y=-mucos32\hat{j}-mvcos32\hat{j}=-2mvcos32

P_y=-1.549\hat{j} kg-m/s

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A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.70 cm wide and 12.0 m long. Between the sheets is a mic
KIM [24]

Answer:

2.121876 mC

Explanation:

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A = Area = 0.037\times 12\ m^2

d = Thickness = 0.0225 mm

E = Dielectric strength = 1\times 10^8\ V/m

k = Dielectric constant = 5.4

Capacitance is given by

C=\dfrac{k\epsilon_0A}{d}\\\Rightarrow C=\dfrac{5.4\times 8.85\times 10^{-12}\times 0.037\times 12}{0.0225\times 10^{-3}}\\\Rightarrow C=9.43056\times 10^{-7}\ F

Maximum voltage is given by

V_m=E_md\\\Rightarrow V_m=1\times 10^8\times 0.0225\times 10^{-3}\\\Rightarrow V_m=2250\ V

Maximum charge is given by

Q_m=CV_m\\\Rightarrow Q_m=9.43056\times 10^{-7}\times 2250\\\Rightarrow Q_m=0.002121876\ C=2.121876\ mC

The maximum charge that can be stored in this capacitor is 2.121876 mC

4 0
3 years ago
How many cubs can a panda have at once and how long does it take for a mother panda to give birth?
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I believe that pandas can only have 1 cub at a time. (Online it says 1.5 cubs but I’m not quite sure how half a cub would work) Their gestation period (how long it takes them to have their cub) is 3-5 months. This is for a giant panda.
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Explanation:

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at a particular instant a hot air balloon is 100m in the air and decending at a constant speed of 2m/s at this exact instant a g
labwork [276]
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Explanation:

Consider the vertical motion of ball

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 2 m/s

        Acceleration, a = 9.81 m/s²  

        Displacement, s = 100 m      

     Substituting

                      s = ut + 0.5 at²

                      100 = 2 x t + 0.5 x 9.81 xt²

                      4.905t²  + 2t - 100 = 0

                     t = 4.32 s    or   t = -4.72 s

                    After 4.32 seconds the ball reaches ground.

Now we need to find horizontal distance traveled by ball in 4.32 seconds.

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 20 m/s

        Acceleration, a = 0 m/s²  

        Time, t = 4.32 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 20 x 4.32 + 0.5 x 0 x 4.32²

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She will find the ball at a horizontal distance of 86.4 m from landed location

5 0
4 years ago
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Answer:

The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

Explanation:

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We need to calculate the value \vec{v}\times\vec{B}

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We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

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Put the value into the formula

\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)

\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}

|F|=2.6\times10^{-9}\ N

Hence, The magnitude of the magnetic force this particle experiences is 2.6\times10^{-9}\ N.

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