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Artist 52 [7]
3 years ago
12

PLEASE HELP!! DUE IN 40 MINUTES!!

Physics
1 answer:
Irina18 [472]3 years ago
6 0

A frame of reference can be thought of as the state of motion of the observer of some event. For example, if you're sitting on a lawn chair watching a train travel past you ... you could even watch a glass of water sitting on a table inside the train move ... This seems like a simple and obvious example, yet when you take a step

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A rectangular dam is 101 ft long and 54 ft high. If the water is 35 ft deep, find the force of the water on the dam (the density
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To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.

P = \rho h

Here,

h = Depth average

\rho = Density

Moreover,

\text{Density of water}= \rho = 62.4lb/ft^3

Replacing,

P = (62.4lb/ft^3)(\frac{35}{2}ft)

P = 1092 lb/ft^2

Finally the force

\text{Force} = \text{Pressure}\times \text{Area of dam with water acting on it}

F = 1092lb/ft^2(101ft*52ft)

F = 5.735*10^6lbf

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2 years ago
The force measured to move a sled was 10 N and the sled was moved 10 meters,
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Answer:

work done would be I don't know

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Why does buying locally grown fruits and vegetables decrease your carbon footprint?
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C. less fuel used to deliver
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3 years ago
Read 2 more answers
1. Which has more momentum: a bowling ball with a velocity of 7.0 m/s or a basketball with a
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kenitec energy

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because kinetic and mass have same

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3 years ago
Sonar is used to determine the speed of an object. A 38.0-kHz signal is sent out, and a 40.0-kHz signal is returned. If the spee
ANEK [815]

Answer:

The velocity is  v  =  8.743 \ m/s

Explanation:

From the question we are told that

    The frequency of the signal sent out  is  f_s  =  38.0 \ kHz  =  38.0 *10^{3} \ Hz

    The frequency of the signal received is  f_r  =  40.0 \ kHz  =  40.0 *10^{3} \ Hz

     The  speed of sound is  v_s  =  341 \ m/s

Generally the frequency of the sound received is  mathematically represented as

         f_r =  f_s  [\frac{v_s  + v}{v_s  - v} ]

where v is the velocity of the object

       =>      40 *10^{3} =  38 *10^{3} *   [\frac{341  + v}{341  - v} ]

       =>      1.05263 = \frac{341+v }{341-v}

       =>   358.94 - 1.05263v  =  341 + v

      =>    17.947 =  2.05263 v

      =>    v  =  8.743 \ m/s

7 0
3 years ago
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