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serious [3.7K]
2 years ago
13

tom’s first carry of a football game resulted in a 5 yard loss his next carry was 12 1/2 if he finished the game with 3 carries

for 26 yards how far was the third carry
Mathematics
1 answer:
Mnenie [13.5K]2 years ago
5 0

Answer:

18.5 yards

Step-by-step explanation:

Tom's first carry was -5 yards and his second was +12.5 yards. If we know he finished with 26 yards we can make a simple equation to try and find the distance of his third carry. We let the letter c be a variable that represents the distance of his third carry.

(-5) + (12.5) + c = 26

This means his first carry + second carry + third carry = carry total

We can simply the left hand side

7.5 + c = 26

Now we move the 7.5 to the right side by subtracting it.

c = 26 - 7.5 \\c = 18.5

So Tom's third carry was for 18.5 yards!

Hope this helps!

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Step-by-step explanation:
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Ok: For number 1

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Number 6

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Hope It helps!!!!

7 0
1 year ago
Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th
bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

8 0
3 years ago
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Answer:

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3 years ago
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Answer:

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2 years ago
How do i simplify this problem?<br><br>12r+5s-7T+9s-4r​
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Answer: To simplify this problem you combine the like terms in the equation (numbers with the same variables.)

Demo: 12r + -4r = 8r

4 0
3 years ago
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