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My name is Ann [436]

3 years ago

9

In one season,Kim ran 18 races. This was four fewer races than twice the number of races Kelly ran. How many races did kelly run

?

2 answers:

Furkat [3]3 years ago

5 0

Answer:

11 races

Step-by-step explanation:

The reason being that 18 is 4 less than twice the number Kelly ran. 18+4=2x when x equals the races Kelly ran. so, 18+4=22 so 22=2x. if you divide each side by 2, you get 11=x. so, kelly ran 11 races

Svet_ta [14]3 years ago

4 0

Answer:

44

Step-by-step explanation:

18+4=22 time 2 =44

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$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c | } \\ \bf{Part \: A} & \bf \footnotesize{The \: decimal \: form \: of \: the \: rational \: number \: \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}} \\ \\ \hline \\ \bf{Part \: B}& \: \bf \footnotesize{The \: value \: of \: \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \\ \hline \\ { \bf Part \:C \: }& \: { \bf\footnotesize{On \: simplifying \: \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. \: \: \: \: \: \: \: \: }} \\ \\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

$\bf \underline{Answer-} \\$

${ \bf{Part \: A \: | \: \footnotesize{The \: decimal \: form \: of \: the \: rational \: number \: \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}}}}$

${ \bf{Part \: B \: | \: \footnotesize{The \: value \: of \: \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3 }}}$

$\bf \underline{Step \:by \:step\: Explanation-} \\$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \sqrt[4]{(9)^{ - 2} } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \sqrt[ \cancel4]{(9)^{ \cancel{ - 2}} } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \sqrt{9^{ - 1} } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ {3}^{ - 1 } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \dfrac{1}{3} }}$

${ \sf \: \: \: \: \: : \: \: \implies3}$

${ \bf Part \:C \: } | \: { \bf\footnotesize{On \: simplifying \: \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. }}$

${~~~\sf ~~:~~\implies (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7})}$

${~~~~\sf ~:~~\implies 5+ \cancel{3 \sqrt{7}} + 12 \cancel{ - 3 \sqrt{7}}}$

${~\sf ~~~~:~~\implies 17}$

$\underline{\rule{200pt}{2.5pt}}$

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Answer:

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Step-by-step explanation:

Given:

The scale on blueprint was 1/4 inch = 1 foot.

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Now, to find the dimensions on the blueprint.

Let the dimensions on the blueprint be $x$ by $y.$

As, given the scale on blueprint:

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So, $\frac{1}{4}\ inch$ is equivalent to 1 foot.

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Now, solving by cross multiplication method:

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<em>By cross multiplying we get:</em>

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$64=y$

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