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Grace [21]
3 years ago
7

The equation below describes a proportional relationship between x and y. What is the constant of

Mathematics
1 answer:
vovangra [49]3 years ago
6 0
The constant of proportionality is 7
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Convert standard to slope-intercept forms. 1. Standard form: 10x − 7y = −8
garri49 [273]

Answer:

Step-by-step explanation:

-7y = -10x - 8

y = 10/7x + 8/7

8 0
3 years ago
Which one is equivalent <br><br> Look at the pic
Paha777 [63]
(3/5)³

=(3³)/(5³)

=27/125

---------------

As:

3*3*3=27

And:

5*5*5=125
6 0
3 years ago
Read 2 more answers
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ahrayia [7]

Answer:

13818

I think that is your answer

5 0
3 years ago
What are the domain and range of f(x) = log(x+b) - 4?
Gnesinka [82]

Answer:

I'm probably to late but i took the test and the answer is B.

domain: x > –6; range: all real numbers.

Hope This Helped!

8 0
3 years ago
Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope
Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

\pi = \frac{179}{523} = 0.3423

Then the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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