The equation below describes a proportional relationship between x and y. What is the constant of

George's page contains twice as many typed words as Bill's page and Bill's page contains 50 fewer words than Charlie's page. If

Deffense [45]

I think bills were 60 words because charlie was 210 so bill was 50 fewer so he is 60 and George will be twice as bills s his will be 80 words

5 0

3 years ago

1. En una biblioteca quieren comprar una computadora que

miss Akunina [59]

Answer:

678.74

that might be the question since I don't really understand what it says really

8 0

3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago

What is the value of yearly compensation package that includes $65,000 salary the forecast of a $350 Dollar per month health ins

Klio2033 [76]

Answer:

$69560

Step-by-step explanation:

The yearly compensation package includes a yearly salary of $65000, the health insurance plan of $350 per month and a life insurance premium of $30 per month.

Total compensation in health insurance plan is $(350 × 12) = $4200

Total compensation in life insurance premium is $(30 × 12) = $360

Therefore, total yearly compensation package is $(65000 + 4200 + 360) = $69560 (Answer)

4 0

3 years ago

40 POINTS PLEASE HELP!

White raven [17]

Answer:

-1.70588235294

1. X3, 15x - 10y = 80 15x - 7y = 51

-17y = 29

2. 8 = 1/60 + a. 8 - 1/60 = 7.98333333333

6 = 1/80 + b. 6 - 1/80 = 5.9875

13.9708333333

3. I genuinely dont know sorry.

4. Pencil = $0.05. Pen = $1.05

Step-by-step explanation:

7 0

3 years ago