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BabaBlast [244]
3 years ago
5

Please helppp! I need help ASAP!

Mathematics
1 answer:
adoni [48]3 years ago
6 0

H is the answer.  All they are asking is for you to plug in different numbers for x in each equation and see what one works out.  H is the correct answer.

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prohojiy [21]
I got an answer of 18. 
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What is the volume of the cup in gallons
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1 cup = 0.0625 gallon
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A vector is in standard position, with its terminal point in the second quadrant and an x-coordinate of –5. The vector has a mag
joja [24]

a.

The y-coordinate of the vector with its terminal point in the second quadrant is 6.

The magnitude of the vector, r = √(x² + y²) where x = x-coorcinate of vector = -5 and y = y-coordinate of vector.

Since r = √61 and r = √(x² + y²)

Making y subject of the formula, we have

y = √(r² - x²)  

Substituting the values of the variables into the equation, we have

y = √((√61)² - (-5)²)  

y = √(61 - 25)  

y = ±√36

y = ±6

Since r is in the second quadrant, its y-coordinate is positive.

So, y = 6

So, the y-coordinate of the vector with its terminal point in the second quadrant is 6.

b.

The direction angle of the vector with its terminal point in the second quadrant is 130°

The direction angle of the vector is gotten from tanФ = y/x

Subsstituting x and y into the equation, we have

tanФ = y/x

tanФ = 6/-5

tanФ = -1.2

tan(180° - Ф) = 1.2

Taking inverse tan of both sides, we have

180° - Ф = tan⁻¹(1.2)

180° - Ф = 50.2°

Ф = 180° - 50.2°

Ф = 129.8°

Ф ≅ 130° to the neares whole number

The direction angle of the vector with its terminal point in the second quadrant is 130°.

Learn more about vectors here:

brainly.com/question/18478651

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B17%7D%20%20%5Cdiv%20%20%5Cfrac%7B7%7D%7B10%7D%20" id="TexFormula1" title=
Lilit [14]

Your answer is 110/119

11/17 Divided By 7/10

11 * 10

17 * 7

110/119

That number can't be simplified, so that is your final answer.

Best of luck,

    - Ari -

8 0
3 years ago
Read 2 more answers
Divide the combinations.<br><br> 60C3 / 15C3
Mariulka [41]
I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number


nCr=\frac{n!}{r!(n-r)!}
so
\frac{60C3}{15C3}=
\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }=
( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})=
( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})=
\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}=
\frac{(60!)(12!)}{(57!)(15!)}=
\frac{(60!)}{(57!)(15)(14)(13)}=
\frac{(60)(59)(58)}{(15)(14)(13)}=
\frac{(30)(59)(58)}{(15)(7)(13)}=
\frac{(6)(59)(58)}{(3)(7)(13)}=
\frac{6844}{91}
4 0
3 years ago
Read 2 more answers
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