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3 years ago

PLEASE HELP FAST !!!!! PLEASEEEEEEEE The cost of go-karting is dollars for the

Mathematics

1 answer:

elixir [45]3 years ago

3 0

you pay x for ten laps an you pay y for every additional lap you just multiply y by seven an add x

so all an all your answer would be (B)

You might be interested in

Does the residual plot show that the line of best fit is

Iteru [2.4K]

Answer:

$e_1 = 3.5-4.06= -0.56$

$e_2 = 2.3-2.09= 0.21$

$e_3 = 1.1-0.12= 0.98$

$e_4 = -2.2-(-1.85)= -0.35$

$e_5 = -4.1-(-3.82)= -0.28$

The plot is on the figure attached. And we can see that the residuals shows a curved pattern so then the best conclusion for this case would be:

Yes, the points are in a curved pattern.

Step-by-step explanation:

The correct formula for the residuals is given by:

$e_i =y_i -\hat y_i$

Who represent the observed value minus the predicted. We can find the individual residuals and we got:

$e_1 = 3.5-4.06= -0.56$

$e_2 = 2.3-2.09= 0.21$

$e_3 = 1.1-0.12= 0.98$

$e_4 = -2.2-(-1.85)= -0.35$

$e_5 = -4.1-(-3.82)= -0.28$

The plot is on the figure attached. And we can see that the residuals shows a curved pattern so then the best conclusion for this case would be:

Yes, the points are in a curved pattern.

4 0

3 years ago

Mariah Jacobsen is the marketing manager at ABC Electronics, a major consumer electronics supplier in the northwest. Over the la

o-na [289]

Answer:

0.6568 = 65.68% probability that she would be correct.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

45000, 45500, 44500, 46000 and 44000 units. This rate of sales is considered average for the product over the last twenty years or so.

This means that:

$\mu = \frac{45000 + 45500 + 44500 + 46000 + 44000}{5} = 45000$

Standard deviation of 1500 units.

This means that $\sigma = 1500$

What is the likelihood that she would be correct if she predicts sales between 43000 and 46000?

This is the pvalue of Z when X = 46000 subtracted by the pvalue of Z when X = 43000. So

X = 46000

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{46000 - 45000}{1500}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486

X = 43000

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{43000 - 45000}{1500}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918

0.7486 - 0.0918 = 0.6568

0.6568 = 65.68% probability that she would be correct.

5 0

3 years ago

Plz help, I don't get it

amm1812

Step-by-step explanation:

$(a+b)^{2} =a^{2} +2ab+b^{2}$

e.g.

$(x+9)^{2} =x^2+2(x)(9)+81$

$(x+9)^{2} =x^2+18x+81$

8 0

3 years ago

In the diagram, how many angles are supplementary but not adjacent angles with angle 7?

Kazeer [188]

The answer is zero.

If any of the pairs of lines were parallel, there would be some same-side interior angles or such that would be supplementary. However, since the lines are not parallel lines crossed by a transversal, the only ones guaranteed to be supplementary to angle 7 are the ones adjacent to it that form a linear pair.

7 0

2 years ago

A drone builder states in their terms of conditions that the battery for their foldable drone will last for more than 4 hours of

ExtremeBDS [4]

Answer:

The manufacturer's claim is not supported

Step-by-step explanation:

The time duration the battery of the foldable drone is said to last, μ = 4 hours

The number of drones that were tested, n = 10 drones

The sample mean, $\overline x$ = 4.2 hours

The standard deviation, s = 0.4 hours

The hypothesis test level of significance = 0.5

The null hypothesis, H₀; μ = 4

The alternative hypothesis, Hₐ; μ ≠ 4

The test statistic is given as follows;

$t=\dfrac{\bar{x}-\mu }{\dfrac{s }{\sqrt{n}}}$

We get;

$The \ test \ statistic, \ t =\dfrac{4.2 - 4}{\dfrac{0.4}{\sqrt{10} } } \approx 1.58113883008$

Therefore, the test statistic, t ≈ 1.58

The degrees of freedom, d. f. = n - 1

For n = 10, we have;

The degrees of freedom, d. f. = 10 - 1 = 9

From the t-table at 0.5 level of significance, the critical-t = 0.7

Given that the test statistic is larger than the critical-t, we reject the null hypothesis and there is enough statistical evidence to suggest that the manufacturer claim is not supported and that the mean is not 4 hours as claimed.

7 0

2 years ago