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kirza4 [7]
4 years ago
6

Need help to find the perimeter please!

Mathematics
2 answers:
ipn [44]4 years ago
6 0

Answer:

The answer to your question is 32"

Step-by-step explanation:

To find the perimeter, just sum all the lengths of the three sides, do not consider the dotted line, so

Perimeter = 10 + 10 + 12

Perimeter = 32"

Alinara [238K]4 years ago
5 0

Answer:

32

Step-by-step explanation: 10+10+12=32

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The orginal price is 72 because 52 plus 20 is 72 which should be the regular original price. if a middle schooler like me can do it im sure you can toooo
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4 years ago
The lengths of three
True [87]

Answer:

90 cm, 180 cm, 240 cm

Step-by-step explanation:

Let the lengths of sides of the triangle be 3x, 6x and 8x

\therefore \: 3x + 6x + 8x = 5.1 \: m \\ \therefore \: 17x = 510 \: cm \\ \therefore \: x =  \frac{510}{17}  \\  \therefore \:x = 30 \: cm \\  \implies \\ 3x = 3 \times 30 = 90 \: cm \\ 6x = 6 \times 30 = 180 \: cm \\ 8x = 8 \times 30 = 240 \: cm

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4 0
3 years ago
PLEASE ANSWER ASAP! SHOW ALL WORK! WILL GIVE BRAINLIEST!
Iteru [2.4K]

1) x^2=x\cdot x, and x(x+3)=x^2+3x. Subtracting this from the numerator gives a remainder of

(x^2-13x-48)-(x^2+3x)=-16x-48

-16x=-16\cdot x, and -16(x+3)=-16x-48. Subtracting this from the previous remainder gives a new remainder of

(-16x-48)-(-16x-48)=0

This means that

\dfrac{x^2-13x-48}{x+3}=x-16

2) 3x^3=3x^2\cdot x, and 3x^2(x+2)=3x^3+6x^2. Subtracting this from the numerator gives a remainder of

(3x^3-x^2-7x+6)-(3x^3+6x^2)=-7x^2-7x+6

-7x^2=-7x\cdot x, and -7x(x+2)=-7x^2-14x. Subtracting this from the previous remainder gives a new remainder of

(-7x^2-7x+6)-(-7x^2-14x)=7x+6

7x=7\cdot x, and 7(x+2)=7x+14. Subtracting this from the previous remainder gives a new remainder of

(7x+6)-(7x+14)=-8

This means that

\dfrac{3x^3-x^2-7x+6}{x+2}=3x^2-7x+7-\dfrac8{x+2}

3) x+2 will be a factor of x^3+3x^2-10x-24 if dividing the latter by x+2 leaves a remainder of 0.

x^3=x^2\cdot x, and x^2(x+2)=x^3+2x^2. Subtracting this from the numerator gives a remainder of

(x^3+3x^2-10x-24)-(x^3+2x^2)=x^2-10x-24

x^2=x\cdot x, and x(x+2)=x^2+2x. Subtracting this from the previous remainder gives a new remainder of

(x^2-10x-24)-(x^2+2x)=-12x-24

-12x=-12\cdot x, and -12(x+2)=-12x-24. Subtracting this from the previous remainder gives a new remainder of

(-12x-24)-(-12x-24)=0

and since the remainder is 0, x+2 is indeed a factor of x^3+3x^2-10x-24.

5 0
3 years ago
Add my discord yuuki#4545 ill help you personally with anything math related
mote1985 [20]

Answer:

ok thx

Step-by-step explanation:

4 0
3 years ago
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