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topjm [15]
3 years ago
6

A sample of a gas in a rigid cylinder with a movable piston has a volume of 11.2 liters at STP. What is the volume of this gas a

t 202.6 kPa and 300. K?
a) 5.10 L b) 6.15 L
c)22.4 L d) 24.6 L
Chemistry
1 answer:
posledela3 years ago
6 0

Given that the volume of  cylinder at STP = 11.2 L

Standard temperature = 273 K

Standard pressure = 1 atm

Calculating the volume of gas at 202.6 kPa and 300. K:

Applying the combined gas law,

\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

P_{1} =1 atm

V_{1}=11.2 L

T_{1}=273K  

P_{2}= 202.6 kPa*\frac{1 atm}{101.325 kPa} =2 atm  

V_{2}= ?

T_{2}=300. K  

Plugging in the values and calculating final volume:

\frac{(1atm)(11.2L)}{(273 K)} =\frac{(2atm)(V_{2})}{(300K)}

V_{2}=6.15 L

Therefore the correct answer will be, b) 6.15 L


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