Question

A sample of a gas in a rigid cylinder with a movable piston has a volume of 11.2 liters at STP. What is the volume of this gas at 202.6 kPa and 300. K?
a) 5.10 L b) 6.15 L
c)22.4 L d) 24.6 L

Answer 1

Given that the volume of  cylinder at STP = 11.2 L

Standard temperature = 273 K

Standard pressure = 1 atm

Calculating the volume of gas at 202.6 kPa and 300. K:

Applying the combined gas law,

$\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$P_{1} =1 atm$

$V_{1}=11.2 L$

$T_{1}=273K$  

$P_{2}$= $202.6 kPa*\frac{1 atm}{101.325 kPa} =2 atm$  

$V_{2}= ?$

$T_{2}=300. K$  

Plugging in the values and calculating final volume:

$\frac{(1atm)(11.2L)}{(273 K)} =\frac{(2atm)(V_{2})}{(300K)}$

$V_{2}=6.15 L$

Therefore the correct answer will be, b) 6.15 L