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Vladimir79 [104]
3 years ago
9

Answer anybody, confused

Chemistry
1 answer:
jeka57 [31]3 years ago
7 0

I'm just taking a self educated guess of A sorry if I'm wrong :C

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Read 2 more answers
In a five-fold serial dilution of a 20 ug/mL solution, all tube dilutions are 1/5. What is the substance concentration in the th
sergij07 [2.7K]

Answer:

In the third tube, the concentration is 0.16 ug/mL

Explanation:

In the first step, the solution is diluted by 5. Then, the concentration will be

20 ug/mL / 5 = 4 ug/mL

Then, in the second step this 4 ug / ml solution is diluted by a factor of five again:

4 ug /ml / 5 = 0.8 ug/mL

This solution is then diluted again by 5 and the concentration in the third tube will be then:

0.8 ug/mL / 5 = <u>0.16 ug/mL </u>

<u />

Another way to calculate this is to divide the original concentration by the dilution factor ( 5 in this case) elevated to the number of dilutions. In this case:

Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL

3 0
3 years ago
Please help, thank you! :D
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