The carbonyl stretch of an amide is typically found around 1,675 wavenumbers; while, the carbonyl stretch of an ester is typical
ly found around 1,725 wavenumbers. Using complete sentences, explain the observed difference in carbonyl stretches for these two functional groups.
1 answer:
Answer:
Explanation:
In the attached file , the resonance structure of amide and ester has been given . One can find that due to oxygen being more electronegative than nitrogen , the contribution of second resonance structure is more . Hence the double bond character of carbonyl bond ( =C=O ) as double bond is less . It is more in the form of single bond . ( see the resonance structure )
On the other hand it is not so in ester because of absence of nitrogen atom. Here carbonyl group is more in the form of double bond . The stretching wave number for double bond is more because it has greater energy .
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Answer:
1.3×10⁻³ M
Explanation:
Hello,
In this case, given the dissociation reaction of acetic acid:
We can write the law of mass action for it:
Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change due to the dissociation extent, we are able to rewrite it as shown below:
Thus, via the quadratic equation or solve, we obtain the following solutions:
Obviously, the solution is 0.00133M which match with the hydronium concentration, thus, answer is: 1.3×10⁻³ M in scientific notation.
Regards.