Answer:
Survey
Step-by-step explanation:
Answer:
0.1587
Step-by-step explanation:
Given the following :
Mean (m) of distribution = 64 inches
Standard deviation (sd) of distribution = 2 inches
Probability that a randomly selected woman is taller than 66 inches
For a normal distribution :
Z - score = (x - mean) / standard deviation
Where x = 66
P(X > 66) = P( Z > (66 - 64) / 2)
P(X > 66) = P(Z > (2 /2)
P(X > 66) = P(Z > 1)
P(Z > 1) = 1 - P(Z ≤ 1)
P(Z ≤ 1) = 0.8413 ( from z distribution table)
1 - P(Z ≤ 1) = 1 - 0.8413
= 0.1587
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
I believe you cant fix one rather you need a new one. It runs about 300 plus labor
