Answer:
c = -12
Step-by-step explanation:
Quadratic Standard Form: ax² + bx + c
Step 1: Write equation
3x² + 6x = 12
Step 2: Subtract 12 on both sides
3x² + 6x - 12 = 0
Here, we have the standard form of the quadratic. We see that our c = -12
M = (22 - 7)/(8 - 5) = 15/3 = 5
<span>using point (5, 7) </span>
<span>y - 7 = 5(x - 5) in point-slope form </span>
<span>y - 7 = 5x - 25 </span>
<span>y = 5x - 18 in slope-intercept form.</span>
X²+15x+36<0
at first solve quadratic equation
D=b²-4ac= 225-4*1*36= 81
x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3
we can write x²+15x+36<0 as (x+12)(x+3)<0
(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set
or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality
B. 45 items x $2 = 90$. 90 + the 25 from the beginning = 115
Answer:
9964
Step-by-step explanation: