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inna [77]
3 years ago
6

I need serious help please

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
Subtract 16x from each side. Then divide each side by 16, and It'll say " b = something " . That's the answer. Seriously.
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Write the following in terms of sine theta only.<br> cotangent
Ulleksa [173]
I don’t exactly know what you’re asking, but cotangent = cosine/sine or another way of writing it is sine = cosine/cotangent
6 0
2 years ago
Kyle is buying a $220 bicycle. If the bicycle is on sale for 35% off, how much will he save? ​
Mrac [35]

Answer:

D

Step-by-step explanation:

Discount = 35% of 220

              = \dfrac{35}{100}*220\\\\= 7 * 11

              = $ 77

Amount saved =$ 77

8 0
2 years ago
Subtracing 3x2+4x-5 from 7x2-3x from this polynomial the difference is
kolezko [41]
7x^2-3x - (3x^2 +4x -5)  multiply negative one across the entire second term

7x^2 - 3x -3x^2 -4x +5

4x^2 -7x +5
4 0
3 years ago
Two different lines lie in the same plane.
nikitadnepr [17]

Answer:

Two lines, both in the same plane, that never intersect are called parallel lines. Parallel lines remain the same distance apart at all times. The symbol // is used to denote parallel lines.

how to prove that two lines are equal: If two lines are cut by a transversal and the alternate exterior angles are equal, then the two lines are parallel. Angles can be equal or congruent; you can replace the word "equal" in both theorems with "congruent" without affecting the theorem. So if ∠B and ∠L are equal (or congruent), the lines are parallel.                                 therefore the answer is E. The two lines are everywhere equidistant.

8 0
2 years ago
Read 2 more answers
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
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