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densk [106]
3 years ago
6

Need help with this please

Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0

Answer:

1. 2(k + 3)

2. 3. 75 + k

Step-by-step explanation:

1. 2x + 6

Since, 2 is a common factor of 2 and 6, we can take that common outside.

So, 2x + 6 = 2(x + 3)

Note that in the initial expression, this 2 was distributed to arrive at 2x + 6.

2. (1.5 + k) + 2.25

This is simple addition. We can simply remove the brackets to have:

1.5 + k + 2.25

Since, the like terms can be added, we will have:

1.5 + 2. 25 + k

= 3. 75 + k

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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
What is 2/3 + 3/4 I don’t understand it at all
victus00 [196]

Answer:

6/12 or half

Step-by-step explanation:

this would be the answer because the lowest common denominator of 4 and 3 is 12 so you'd multiply them you'd get 12 then multiply 2 and 3 and get six therfore the answer is 6/12 or 1/2

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Simplify this expression
antiseptic1488 [7]

Answer:

2/(3x-2)²

Step-by-step explanation:

4x²-6x³-2x²+6x³/4x²-6x³-6x³+9x^4=

2x²/4x²-12x³+9x^4=

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4 years ago
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