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evablogger [386]
4 years ago
14

I need help please?!!!!!

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
8 0

Answer:

negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative

Vlada [557]4 years ago
3 0

Answer:

Negative

Step-by-step explanation:

An odd power on a negative value doesn't make it positive.

An even power on a negative value makes it positive.

Power is 101, which is odd. So the value remains negative

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**I WILL DELETE ANY BS OR WRONG ANSWERS**
pychu [463]

Answer:

  • See below

Step-by-step explanation:

<u>The sequence is as per attached: rotation >> translation >> reflection:</u>

  • 1. Rotate 120 degrees anticlockwise around B,
  • 2. Then translate B to B' and
  • 3. Reflect over segment BA.

5 0
2 years ago
Given g(x)=4x-2/5 find the inverse
docker41 [41]

Answer:

g^-1(x)=1/4x+1/10

Step-by-step explanation:

y=4x-2/5

x=4y-2/5

4y-2/5=x

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20y=5x+2

y=1/4x+1/10

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6 0
2 years ago
Help with my math plesae 100 POINTS POINT STEALING = REPORT
andre [41]

Answer:

Sides lengths of a ,b, c such that a^2+b^2 =c^2, triangle ABC is a right triangle

Step-by-step explanation:

Sides lengths of a ,b, c such that a^2+b^2 =c^2, triangle ABC is a right triangle

The converse is interchanging what is given and what is proven.

7 0
3 years ago
Read 2 more answers
A bag holds 20 ounces of rice. About how many grams of rice is in the bag? left parenthesis 1 oz approximately equal to 28.3 g r
Alex787 [66]
There are approx.  566 g. of rice in that bag. 
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6 0
3 years ago
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Gopal spent 3/5 of his money in the first week and 1/3 of the remainder in the second week. He spent $110 altogether. How much m
saul85 [17]
First let's find out what 1/3 of 3/5 is. To do that, we have to multiply 1/3 by 3/5 which equals 3/15, which simplifies to 1/5. 

Since we know that Gopal spent 110, we know that 110 is equal to 4/5. We have to find the last 1/5. To do this, divide 110/5 = 22

The answer is 22 :)

I hope this helps! :)
5 0
3 years ago
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