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goldfiish [28.3K]
3 years ago
8

Use substitution to solve the linear system of equations. y = -3x + 1 y = 2x - 4

Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0
(1,-2) will be your answer
nevsk [136]3 years ago
5 0

Answer:

The answer is 1,-2

Step-by-step explanation:

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If 21 - 22, which lines are parallel?
choli [55]

Answer:

C

Step-by-step explanation:

n and p are parallel since angle 1 and and 2 are equal

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3 years ago
HI IM NEW HELP IDK WHAT TO DO
Veseljchak [2.6K]
You can ask questions on here and people will answer them the best they can 
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3 years ago
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-5(11-3t) = -6t - 4 what does t equal?
Inessa [10]
-5(11-3t) = -6t -4

distribute -5 to the parentheses

-55+15t = -6t -4

isolate t; add -6t from both sides

-55+21t = -4

add 55 from both sides

21t = 51

divide t

t = 2.4 (rounded)
6 0
3 years ago
Calculate the surface area or a sphere or radius 7.3 cm.
belka [17]

Answer:

1436.755 cm³

Step-by-step explanation:

Input Data :  

Length = 7 cm

Objective :  

Find what is volume of the sphere for given input data?

Formula :

Volume =

4πr3

3

Solution :

Volume =

4 x 3.1416 x 73

3

=

4 x 3.1416 x 343

3

=

4310.2651

3

Volume = 1436.755 cm³

8 0
4 years ago
A survey was conducted among 78 patients admitted to a hospital cardiac unit during a​ two-week period. The data of the survey a
serious [3.7K]

Sets and set operations are ways of organizing, classifying and obtaining information about objects according to the characteristics they possess, as objects generally have several characteristics, the same object can belong to several sets, an example is the subjects of a school , where students (objects) are classified according to the subject they study (set).

The <em>intersection</em> of sets is a new set consisting of those objects that simultaneously possess the characteristics of each intersected set, the intersection of two subjects will be those students who have both subjects enrolled.

The <em>union</em> of sets is a new set consisting of all the objects belonging to the united sets, the union of two subjects will be all students of both courses.

In this case there are three sets B, C and S of which we are given the following information:

Answer

n(BꓵSꓵC)=5

n(BꓵS)=10 – 5 = 5

n(BꓵC)=12 – 5 = 7

n[(BꓵC)ꓴ(BꓵS)ꓴ(CꓵS)]=21  – 5 – 5 – 7 = 4

n(B)=36 – 5 – 5 – 7 = 19

n(S)=30 – 5 – 5 – 4 = 16

n(C)=34 – 5 – 7 – 4 = 18

7 0
3 years ago
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