We have been given an equation of circle 
. We are asked to find the center and radius of the circle.
First of all, we will write equation of circle is standard form 
, where center of circle is at point (h,k) and radius is r.
Let us complete the square for both x and y.
Adding half the square of coefficient of x and y term, we will get:
Therefore, the center of the circle is 
and radius is 4 units.
9514 1404 393
Answer:
f(x) = x³ +3x² -6x -18
Step-by-step explanation:
In order for there to be a root of √6, there must be a factor of (x-√6). In order for there to be rational coefficients, there needs to be another factor of (x+√6) in the minimal polynomial. Then the minimal polynomial with the required roots is ...
f(x) = (x +3)(x -√6)(x +√6) = (x +3)(x² -6)
f(x) = x³ +3x² -6x -18
Answer:
a: 1/12
b: 1/6
c: 1/2
d: 1/2
e: 1/12
f: 1/3
Step-by-step explanation:
Answer:
it will be broken into 9*what ever x is
Hope This Helps!!!
